Glowplug said:
According to your formula as RPMs INCREASE torque DECREASES
Perhaps you should check your math Chuck. I suspect you may have confused yourself by plugging
engine Torque and HP values in there. As you can see in any
engine torque vs hp curve, you must consider that they BOTH change with RPMs. If you insert a HP value into that formula, you must consult the engine's torque curve to determine the associated torque value at the RPM that produces that HP number. For example, at 2600 RPM the OP L5240 engine is rated to produce 54 engine HP and 45 PTO hp at 2600 engine RPMs. Plugged into the formula, the L5240 is making about 109 pounds of torque at that point.
Works a bit different at the PTO output. Since this is a PTO discussion, I used PTO values. Remember, PTO ratings (HP) are established at 540 PTO rpms, which means how many revs the engine might be turning to obtain 540 at the PTO - is irrelevant to this particular calculation.
Since the OP question involved his L5240, let's solve for the amount of PTO
Torque.
If
HP = Torque*RPM/5252, then
Torque = HP*5252/RPM.
RPM for his Woods 720 a fixed 540,
PTO output (HP) for his L5240 is rated at 45;
so
45*5252/540 = about 438 pounds of torque delivered by the L5840 PTO spline to the tractor side of a slipclutch.
The difference between
engine HP/Torque and
PTO HP/Torque is because of the transmission. After going through
gear reduction, the engine HP/Torque was converted into PTO HP/Torque; HP went down, Torque went up.
//greg//