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  1. #1

    Default Hp.hr/gal

    Please define HP Hour/Gallon

  2. #2
    Super Member RickB's Avatar
    Join Date
    Sep 2000
    Posts
    7,308
    Location
    Eastern NY
    Tractor
    Case 885, Ford 4000

    Default Re: Hp.hr/gal

    The number of horsepower that can be produced for a full hour using one gallon of fuel.
    We have too much gun control.
    What we need is more idiot control.

  3. #3
    Veteran Member MHarryE's Avatar
    Join Date
    Feb 2009
    Posts
    1,365
    Location
    Northeastern Minnesota
    Tractor
    JD 7720; Kubota M135GX, NH TS115A; JD 6230; Kubota L5740

    Default Re: Hp.hr/gal

    Lots of people brag about how little fuel their tractor uses but usage is really dependent on load. For example I am looking at a tractor that uses 9.6 gallons per hour at max engine power but that is 17.98 HP hr/gal. If that same tractor is pulling a smaller implement and therefore is running at only 75% of its max power, it gets 13.98 HP hr/gal. It is using 8.1 gallons per hour so less fuel per hour, but the engine is not running as efficiently at this low power. It is pulling at 75% max power but it is using fuel at 85% of the max rate. I saw a big difference when I swapped my L3710 for a L5740. I use many of the same implements and am therefore running lower on the power curve than I did with my L3710. I burn significantly more fuel to do the same work, but on the other hand I do have the extra capability when I need it.
    JD7720; KubotaM135GX; NH TS115A; JD6230; KubotaL5740

  4. #4
    Gold Member
    Join Date
    Mar 2011
    Posts
    381
    Location
    Florida Ma.
    Tractor
    Ford 1720 SSS 4x4

    Default Re: Hp.hr/gal

    It's call brake specific fuel consumption or (lbs/hphr)
    Meaning hp at the crankshaft with no accessories.
    Most industrial diesel engines will give the specific fuel consumption at various engine speeds and hp.
    Lets say my 1990 Dodge Cummins operating in it痴 sweet spot had a specific fuel consumption of .34 lbs per hp/hp hour.
    If the engine was developing 65hp then you multiply 65x.34 = 22.1 lbs of fuel consumed in 1 hour now divide that by the weight of the fuel which is approx
    7.1lbs and you get 3.11 gph consumed.

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