John_Mc
Elite Member
- Joined
- Aug 11, 2001
- Messages
- 4,045
- Location
- Monkton, Vermont
- Tractor
- NH TC33D Modified with belly pan, limb risers & FOPS. Honda Pioneer 520 & antique Coot UTV
Does anyone have any "real-world" times to brushhog a meadow? I've been asked to help a neighbor with a wildlife habitat practice where he needs to brushhog a meadow once every 2 years. We've already cleared the random rocks, logs, etc. which would be a hazard to mowing. The area is still fairly rough (not a lawn by any stretch of the imagination), so mowing speeds will be moderate. There are still a few obstacles to mow around, but we don't need to worry much about cleaning up the mowing around them. Still, there will be a bit of back-and-forth and extra manuevering.
I know how to calculate a theoretical time. Figuring a 4 foot swath cut with my 5 foot brush mower: 4 ft X 5280 ft/mile X mowing speed in MPH = square feet/hour mowed. Divide that by 43,560 sq ft/acre should give me acres per hour.
However, I've never actually timed myself to see how the real world compares to the formula. I'm guessing I'd be going around 2.5 MPH through this heavy 2 year growth. Sound reasonable? (27 HP at PTO on my tractor). That gives 1.2 acres per hour from the formula, but I'm pretty sure that similar small meadows I've mowed take significantly longer than this.
Hoping some of you have real-world comparisons
I know how to calculate a theoretical time. Figuring a 4 foot swath cut with my 5 foot brush mower: 4 ft X 5280 ft/mile X mowing speed in MPH = square feet/hour mowed. Divide that by 43,560 sq ft/acre should give me acres per hour.
However, I've never actually timed myself to see how the real world compares to the formula. I'm guessing I'd be going around 2.5 MPH through this heavy 2 year growth. Sound reasonable? (27 HP at PTO on my tractor). That gives 1.2 acres per hour from the formula, but I'm pretty sure that similar small meadows I've mowed take significantly longer than this.
Hoping some of you have real-world comparisons