What is the distance between the inner and outer bearing centers for the rear axle? The inner bearing will experience a greater load, the outer bearing should experience the same load, and the axle will see a greater bending moment. On the 1510, the axle is about 2" diameter and 6" from outer bearing to wheel center. A 2" increase in length will increase the bending moment (Moment=ForcexDistance) by 33%.
Assume the rear axle steel is 40,000 PSI steel (standard grade steel). The area of the 2" axle is 3.14 square inches, so that works out to 125,600 pounds of force to fail. Assume the full weight of the 1510 (1250 pounds) with an attachment (400 pounds) all balanced on the one rear wheel with a safety margin of 2, that is 3,300 pounds. Now multiply by the distance to get the bending moment: 8" x 3,300 pounds = 26,400 pounds. The rear axle is still 5 times stronger then that maximum load.
Disclaimer: I am not a structural or mechanical engineer...