Can anyone help me troubleshoot the fuel shut-off system on my BX24? I've seen so many different descriptions of how the system works, I'm not sure what to check, where, and under what conditions.
My problem, which seems to be pretty common, is that turning off the key on my BX24 doesn't turn off the tractor. I can turn it off by pushing in the rod of the fuel shut-off solenoid.
How does the system work? Here is my best guess. While the engine is running, there is no voltage across the input of the solenoid. Turning off the key puts 12V across the solenoid input, moves it, stops the fuel, then removes the 12V after some period of time, maybe 5 seconds. Is this correct?
One obvious problem I have is that the wire running from the loom into the solenoid boot isn't connected to anything inside. I suspect that it is to be attached to the "tab" protruding from the end of the solenoid housing. Is this correct?
When the key is in the "on" position, there is no voltage between the wire and ground. Turning the key off does not appear to put 12V between the wire and ground. This suggests that something is amiss upstream, perhaps a bad ignition switch, fuse, or connection? Is this correct?
I connected a 12V battery to the tractor's ground using a small jumper wire. I then touched a jumper wire connected to the battery "+" terminal to the "tab" protruding from the solenoid housing. There were sparks and the jumper wire started to warm up rapidly, but the solenoid didn't move.
The approach I'd take going forward from here would be to work upstream from the wire that should connect to the solenoid and see if I can find that 12V "pulse" anywhere. Is this a reasonable approach?
If I'm on track, where, physically, should I be checking the voltage? Is there a better way to troubleshoot this system/
Thanks,
Brian
My problem, which seems to be pretty common, is that turning off the key on my BX24 doesn't turn off the tractor. I can turn it off by pushing in the rod of the fuel shut-off solenoid.
How does the system work? Here is my best guess. While the engine is running, there is no voltage across the input of the solenoid. Turning off the key puts 12V across the solenoid input, moves it, stops the fuel, then removes the 12V after some period of time, maybe 5 seconds. Is this correct?
One obvious problem I have is that the wire running from the loom into the solenoid boot isn't connected to anything inside. I suspect that it is to be attached to the "tab" protruding from the end of the solenoid housing. Is this correct?
When the key is in the "on" position, there is no voltage between the wire and ground. Turning the key off does not appear to put 12V between the wire and ground. This suggests that something is amiss upstream, perhaps a bad ignition switch, fuse, or connection? Is this correct?
I connected a 12V battery to the tractor's ground using a small jumper wire. I then touched a jumper wire connected to the battery "+" terminal to the "tab" protruding from the solenoid housing. There were sparks and the jumper wire started to warm up rapidly, but the solenoid didn't move.
The approach I'd take going forward from here would be to work upstream from the wire that should connect to the solenoid and see if I can find that 12V "pulse" anywhere. Is this a reasonable approach?
If I'm on track, where, physically, should I be checking the voltage? Is there a better way to troubleshoot this system/
Thanks,
Brian