I have a 1430 and am contemplating making a 3 pt mower work for it as opposed to spending $4000 on commercial mower which would see rather infrequent use. Would this motor work on a 60” deck for a 1430 or is the HP number going throw wrench in the math equation?
That's a hard thing to say.
That motor is 0.580 cubic inches.
The PT425 60" deck has 3 spindles and blades.
The PTO on the 425 puts out 8GPM at 2500 psi.
I do not know how many RPM it spins that motor, but it could be figured out with the hydraulic calculators at Surplus Center, or a tachometer.
You'd have to find out the GPM and PSI of the 1430 PTO and then determine the cubic inches of a motor that will spin at the RPM you're aiming for on the deck.
I'm guessing the 1430 has higher GPM and PSI, so it would potentially spin the motor too fast. You'd need to compensate with a higher displacement motor to bring the RPMs down, if that's what you determine you need.
So, a 3pt PTO spins at 540 rpm. If it's a 1:1 gearbox on the 3PT mower, it would be easy to figure the 1430's GPM, PSI, and then the displacement of the motor that you'd need to get to spin it at 540 rpm.
If the gearbox on the 3PT mower has a reduction or increase, you'd have to figure that in if you're planning on replacing the gearbox to drive the blades directly with a hydraulic motor. Or, you could place the hydraulic motor right onto the gearbox where the PTO shaft would have been and just figure it for the 540.
Make sense?