jmc
Elite Member
- Joined
- Jul 21, 2003
- Messages
- 2,967
- Location
- SW Indiana
- Tractor
- Ford 1920 4x4 (traded in on Kubota). Case 480F TLB w/4 in 1 bucket, 4x4. Gehl CTL60 tracked loader, Kubota L4330 GST
</font><font color="blue" class="small">( calculating roughly, taken the saw band blade is 3 centimeter wide and the projected bearing surface (equals the wheel diameter) is 55 cm, and the pressure is 2.75 bar (2.75 kg per square centimeter) the max. strain that the tire could put on the saw blade would be 8318 kilogram... I assume /forums/images/graemlins/grin.gif that 8.3 metric tons will do the trick here...)</font>
Renze,
I think a lot of that calculated force is soaked up in stretching the sidewalls of the tire and, therefore, never reaches the blade.
Probably, if you ran that same calculation on the total force in 4 car tires that support the weight of the car, the car's weight would be so small in comparison that there should be almost no tire deflection. Yet the tires do compress because most of that pneumatic force is stretching the sidewalls. (I think.)
John
Renze,
I think a lot of that calculated force is soaked up in stretching the sidewalls of the tire and, therefore, never reaches the blade.
Probably, if you ran that same calculation on the total force in 4 car tires that support the weight of the car, the car's weight would be so small in comparison that there should be almost no tire deflection. Yet the tires do compress because most of that pneumatic force is stretching the sidewalls. (I think.)
John