BB_TX
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<font color=blue>will cause resistance which will increase amp draw </font color=blue>
This is an often stated misconception of electricity. An increase in resistance causes a decrease in current flow. Ohm's law is V=IR (voltage = current times resistance). Or to rearrange, I=V/R (current = voltage divided by resistance). As resistance increases, there is a proportional decrease in current.
A bad connection does cause heating because of a voltage drop across that connection point. This can be thought of as the power loss across that connection. Power(in watts)=VA (volts time amps). Also Power=I(squared)R (current squared times resistance). If the connection were perfect (no resistance) there would be no power loss. As the resistance increases, the power loss is multiplied by the square of the current. That loss grows rapidly as the resistance increases, and thus the heating.
Not trying to stir anything up, just want to clear the issue./w3tcompact/icons/smile.gif
This is an often stated misconception of electricity. An increase in resistance causes a decrease in current flow. Ohm's law is V=IR (voltage = current times resistance). Or to rearrange, I=V/R (current = voltage divided by resistance). As resistance increases, there is a proportional decrease in current.
A bad connection does cause heating because of a voltage drop across that connection point. This can be thought of as the power loss across that connection. Power(in watts)=VA (volts time amps). Also Power=I(squared)R (current squared times resistance). If the connection were perfect (no resistance) there would be no power loss. As the resistance increases, the power loss is multiplied by the square of the current. That loss grows rapidly as the resistance increases, and thus the heating.
Not trying to stir anything up, just want to clear the issue./w3tcompact/icons/smile.gif