Leejohn
Elite Member
What size pins would be needed?
Do the math. Piston area is ス the diameter squared (d/2 x d/2) x pi (22/7 or 3.1417XXXXXXX) x pressure in pounds per square inch yields pounds of force.
180,000 tons is 3.6x exp8 (natural logs) = 2500 psig (for a number for pressure in psig) x area of piston.
Transposing, area of piston = 18000 tons/2500 = 1.44 exp5.
Diving by pi 1.44 exp5/3.14 = ス dia squared (radius squared) = 4.6 exp4 inches (since values are in #/ in squared).
Solving for the diameter in inches = square root of 4.6 exp4 = 2141 x 2 = 4283/12 = a diameter of 35'.
,,,,,,,,nothing else to do this evening :cool2:
Yes, the huge forces are mind boggling, but with hydraulics it comes down to area and pressure and special contrivances to bring them to bear. The high forces, even in the 100s of tons rely on use of multiple cyls applied in pull mode driving a guided platen. In the thousands of tons this becomes the only way physically possible within the strength of materials.yeah guys, sorry, on the tonnage. but in the end 8000 800 80 it still blows my mind so little (in my head) can do so much. Thanks for all the insight and links, lots of reading for sure.
I understand all the math, can do it in my head, not. The DIVING by Pi has me a bit confused, swan, jack knife ,,, what kind do you recommend ?
Smilinjak