What are you trying to figure out? Cylinder length, grapple force, etc ,etc?
Yep, really need more info on this.
Are you trying to find what length cylinder??? Diameter vs Force??? Pivot placements??
Have you already built the grapple??
It is really just simple geometry. You will have 3 pivot pins, 1 on each end of the cylinder, and one where it attaches to the bucket. These three points create a triangle, no matter how far the grapple is open or closed. 2 sides of the triangle are a fixed length and cannot change. The third side can change length (the cylinder) and that will change all 3 angles of the triangle.
All that being said, the formula I would most likely use the most for the various calculations involved with the grapple geometry is the cosine law.
c^2=a^2 + b^2 - 2ABcos(C)
If you are wanting to find the force, that takes a little more math. First you would have to find the force of the cylinder. pi x r^2 x PSI. Then you have to find how much force it is exerting on the grapple in the downward direction ONLY. Cylinders mounted on angles the formula is cylinder force x sin of the angle. That will tell you the force at the cylinder point.
Since the grapple probabally extends beyoned that (think of a lever) the force will be less at the tip of the grapple. How much less depends on the lengths of the grapple, where the pivot is, and where the cylinder is mounted. But it will be a ratio. Think of the pivot as zero. If the cylinder is mounted 12" out on the grapple and the tip is 24" from the pivot (cylinder mounted exactally half way) the ratio is 12:24 or 1:2. You would have exactally half of the force at the tip as you do at the cylinder.
Is this what you are looking for??