MarkLeininger said:
Jim,
I don't understand why they don't make the recommendation based on PTO HP. Then, as you point out, since my PTO HP is 20: 20*.746 = 14.9KW. The rated PTO HP is presumably at 540RPM.
The 746 conversion factor is for an ideal process, i.e. 100% efficiency, which is never realized in real world processes. Not only will you have mechanical losses in the power transmission from the engine to the pto output, but you also have significant mechanical and electrical losses in the generator itself. Oh, considering the generator as a thermodynamically closed, isolated system, you might get pretty close to an ideal case using some sort of magnetic levitation for the bearings, and running it in a hard vacuum with supercooled/superconducting coils, but I wouldn't want to have to either pay for, or maintain something like that.
If you use the rule of thumb of 500 W per Engine HP, you've effectively assumed an overall process efficiency of about 67%. That won't be exact for any given tractor/generator combination, but is in the ballpark of what you'll actually see.
In your calculation, you tacitly assumed a generator efficiency of 100%. You'll actually achieve something on the order of (20 PTO HP X 746 W/HP X ~90% Assumed Generator Efficiency) = ~ 13.4 KW. Your tractor is rated at 27 Engine HP. The 500 W/HP guide applied to your rated engine HP gives ~13.5 KW.
Remember, in any case it's a SWAG and the accuracy in any specific case is open to question. It's usually spec'ed in terms of 500 W per tractor HP instead of something like 670 W per PTO HP because it's easier to calculate in your head and gives a fairly good ballpark result.