glovemeister
New member
- Joined
- Oct 1, 2010
- Messages
- 7
Suppose a chisel plow is to be used in heavy soil conditions where the resistance is 600 pounds per foot of width. Soil condition is considered firm. What size four wheel drive tractor would be needed to pull the chisel at a speed of 6.0 mph if the chisel is 14 feet wide.
I haven't found a formula for this but the knowns are speed desired 6.0 mph, soil resistance 600 lb/ft of width. Width 14 ft wide. 14X600 = 8400 total resistance. Multiply that by 6 mph to get 50,400/375=134.4 required horsepower. However I am just curious as to if this is correct, and what I would need to do to calculate horse power per ft. if I have that I can multiply it by the width of the chisel to get the total required horsepower.
Thanks a bunch!
I haven't found a formula for this but the knowns are speed desired 6.0 mph, soil resistance 600 lb/ft of width. Width 14 ft wide. 14X600 = 8400 total resistance. Multiply that by 6 mph to get 50,400/375=134.4 required horsepower. However I am just curious as to if this is correct, and what I would need to do to calculate horse power per ft. if I have that I can multiply it by the width of the chisel to get the total required horsepower.
Thanks a bunch!