Is it worth the effort?

[2458n]

They are fancy stainless steel wheel covers. Good ones bolt on top of your existing steel wheels and give the truck some "BLING". You will always find them on Commercial wreckers, and other dressed up trucks. I have ran them on one ton dumps untill somebody tears them off with a bob cat. Wholesale they cost around 200.00. Used car lots will always put them on because of the curb appeal.

 

[2458n]

This is a real truck and looks good to me as in Ohio it would be very rusted by now. Only suggestion would be to watch out for those dang little stumps. Tires are pricey for both the truck and tractor.

 

[timswi]

I didn't show the back seat. It's really not even there. It was in such bad shape we threw it out. How are things in Beaver County. I was raised in the area and used to hunt around Raccoon State Park for many years.

Excuse my ignorance, but what are Simulators?

Beaver County is what it always was..I was a kid when the mills went went. Have to drive to Pgh to make an OK living....Still a nice place to be...The people can't be beat.

Simulators are the chrome wheel covers that everyone puts on the dulley "bud" wheels...$150-$200 at Summit Racing...They just look really nice. Certainly not a necessity.

Glad to hear from a Beaver County ex-pat.:thumbsup:

 

[Diamondpilot]

I am with you guys and barter also. Usually for use of dump trucks, ect.

Chris

 

[aczlan]

I am with you guys and barter also. Usually for use of dump trucks, ect.

We use barter for welding/fabrication work with a local shop.
Works out well for all involved.

Aaron Z

 

[Flying MXZ]

18 acres x 43,560 ft^2/ac = 784,080 ft^2 / 5' brushhog (assuming full 5' cut) = 156,816 ft driven / 5280 ft/mile = 29.7 miles. Assume brushhoging at 3 mph (wag) = 89.1 hours. That is a lot of time, but for a free truck in decent shape and the other benefits I would probably do it.

Feel free to correct any of my wrong assumptions.

 

[HHR]

18 acres x 43,560 ft^2/ac = 784,080 ft^2 / 5' brushhog (assuming full 5' cut) = 156,816 ft driven / 5280 ft/mile = 29.7 miles. Assume brushhoging at 3 mph (wag) = 89.1 hours. That is a lot of time, but for a free truck in decent shape and the other benefits I would probably do it.

Feel free to correct any of my wrong assumptions.

29.7 miles at three miles an hour would be around 10 hours.

 

[Diamondpilot]

18 acres x 43,560 ft^2/ac = 784,080 ft^2 / 5' brushhog (assuming full 5' cut) = 156,816 ft driven / 5280 ft/mile = 29.7 miles. Assume brushhoging at 3 mph (wag) = 89.1 hours. That is a lot of time, but for a free truck in decent shape and the other benefits I would probably do it.

Feel free to correct any of my wrong assumptions.

Everything I read when it comes to pricing out mowing jobs is 80% efficiency. This is how the ZTR mowing crews that I maintain equipment for do it.

10 hours is right for perfect conditions, ect. My guess is it will be a 20 hour job just from experience. Thats assuming 80% efficiency and just the time to move obstacles, ect. Mainly trees and rocks.

Chris

 

[Flying MXZ]

29.7 miles at three miles an hour would be around 10 hours.

Yep, that's what I get for trying to do it fast.

 

[slowzuki]

18 acres on a 5 ft hog always takes me about 10 hours. In really rough ground though. I'd say you got a great deal!