ME83
Silver Member
Lets get technical. ... Quick calcs indicate shear of a 3/8 Gr5, 120,000 psi, bolt oin a 2" shear joint takes about 100HP @ 540 rpm. ... Check me on this..
Actually it starts getting very technical. A 3/8" grade 2 bolt shears at 4900 lbs, double that since it is a double shear so 9800 lbs. On a 2" shaft, or 1" from centerline, that would require 117,600 ft*lb of torque. At 540 rpm that is 12,091 hp.
A shear bolt on a spinning shaft like this breaks due to impact, not straight weight or power. The calculations for impact are completely time dependent, which is why such a large force can be exerted. To calculate it, it is not just power being supplied but also the inertia of the brush hog spinning.
The easiest answer is that a grade 5 bolt is roughly 60% stronger than a grade 2. If there is a small gap, a grade 5 will still bend just as much but will require more force. The shear pin is designed to be the sacrificial weak link in the drivetrain, do not change that. A $1.00 bolt is much easier and cheaper to replace than possibly a $200 driveshaft.