I知 betting this generator head powered with a 40 hp diesel will stomp all over the efficiency of a regular person grade pto generator. This head is a quality piece that is probably more efficient than the much smaller and cheaper head. There痴 no parasitic loss to a gear box if it痴 direct drive. There痴 no parasitic loss to the tractor either. And retaining the use of the tractor counts as useful.
I cannot find published efficiency numbers for this head. Heads this "small" are apparently sold exclusively coupled to Cat engines, and the only efficiency-related data Cat publishes is the overall efficiency of the genset (engine + head), and fuel consumption data for various load from 25% load to 100% load. Caterpillar publishes much more detailed specs on their larger units, and they are typically 89% - 94% efficient at 25% load, and 95% - 97% efficient at 100% load.
The head is going to be less efficient at lower loads, as parasitic loss constants will occupy a bigger piece of the pie. I'm thinking that at any given percent of load, there will be the (more or less)
fixed combined loss of generating the rotating field current, plus the load of spinning the fan, plus bearing losses, air drag of the spinning rotor, etc. I will be operating the head exclusively below 15% its rated load, usually 10% or less. So in order to estimate efficiency below 25% I've just taken the numbers from the larger generators and calculated the waste kW @25% load as a fixed parasitic loss, which looks like this:
...90% efficiency at 25% load, that's:
210kw * 0.25 = 52.5kw generated @ 25% load.
(1/0.9) * 58.33 kW mechanical
58.33kW - 52.5kW =
5.8kW (7.7HP) waste
So that's 7.7HP (conservative/worst case) just to spin the thing, with no electrical load.
If I were to utilize this thing at 10.5kW (5% rated load), powering my house, and there was 5.8kW tacked on top, that's only 64% efficiency.
BUT...
I've done the math already on the field current generator and that's 1HP/746W.
Maybe another 1HP for the bearings, rotor drag, etc.
So I think it's reasonable to assume the big fan accounts for about 5HP. It's a pretty big fan.
That fan is designed to move the waste heat of a 210kW load. At 95% efficiency, that's 11kW of waste heat the fan is responsible for getting rid of. I won't be dissipating anywhere near that. I'll have the heat generated by field coil (746W) plus whatever inefficiency of generating 25kW max, so maybe 2kW.
I think I can ditch the fan, or at least shave the blades so that they don't throw nearly as much air.
I think I can this beast within the 95%-97% efficiency realm at
my max load, with a single easy modification.