fried1765
Super Star Member
- Joined
- Jan 6, 2015
- Messages
- 10,089
- Tractor
- Kubota L48 TLB, Ford 1920 FEL, 8N Ford, Gravely 12 HP "Professional", 48" SCAG Liberty
You're gonna remove 30 stumps and then hand till the area, that you estimate to be 1/2-3/4 of an acre? And then use a box blade on a 23hp tractor to change the grade on that area? How deep of an area are you going to drag out of there?
1/2 an acre is 21780 square feet. If you're estimated 1/2 acre is only 100' long, it's 217' wide.
Let's look at it from a side angle. And, let's say you want to regrade 6" deep from one end to the other to "flip" that area.
And let's say its a perfect slope, so it's a 6" high wedge at the far end and 0" at the other end. You really only need to move an area of dirt 50' long by 217'.
50' x 217' = 10850 square feet with an average depth of 3", or 1/4 of a foot.
So divide 10850 by 4 = 2712.5 cubic feet.
There's 27 cubic feet in a cubic yard, so 2712.5 / 27 = 100.46 cubic yards of dirt you have to move.
You're not going to do that with a hand tiller and a box blade on a 23hp tractor in a couple days. You have probably a 1/3 yard bucket. That's the equivalent of about 300 bucket loads of dirt that you're gonna try and pull with a box blade, which won't pull 1/3 of a yard at a time.
Someone can check my math, as I suck at math, but I'm pretty sure that's what it comes out to.
You're way underestimating the size of that job.![]()
"You're way underestimating the size of that job"
"way underestimating" .......commonly done!!