SPYDERLK said:Yes. Motor resistance is very low. If you applied Ohms law to the actual motor resistance you would predict extremely high currents. This resistance doesnt change as the motor spins, but as the motor spins it generates a counter V [opposite from the batt V] called Back EMF. As the motor goes faster so rises BEMF until current limits. - So the resistance of the motor appears to vary with speed. Slow the motor with a load, BEMF drops and current rises. As current rises there is more V lost due to the internal resistance of the batt so the V remaining to feed the motor goes down. The current to a starter is way high at low cranking speeds in cold engine starting applications regardless that the battery may be consuming 2V internally and only delivering around 10V to the starter.
Very few tractor sized 12V batteries will hold up to deliver 12V to a 100+ Amp load-NONE will deliver 13.2V . Thats why I used the 11.5V figure for predicting current consumed by a 2.2kW starter.
larry
Yeah, yeah, mumble, mumble, back emf, rising internal resistance of the battery as it drains, falling of back emf as the starter slows, etc......
Which is why I used the word UNPREDICTABLE.
At the instant the switch is thrown ohm's law pretty much applies, self and mutual inductance will follow, soon, but not at the instant of initial contact.
Have enough cable to take the full stalled load, not the load at free spinning speed.