Soundguy
Old Timer
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- Mar 11, 2002
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This is a simple dc circuit.. Think of it as a voltage divider with multiple test points. You are measuring potential at a point in reference to ground. Test this logic by changing your reference point. Instead of referencing ground, reference before the last light. Also, keep in mind that current (electron current ) flows from negative to positive. These are identical loads in series... each is 'seeing' the exact same current flow, which will then produce the same voltage drop across that component. Keep in mind that voltage drop is an effect of current flow. With no current flow, there is no voltage drop.
Soundguy
"Each light will actually "see" 3 volts less than the previous, although each light will only be using or dropping 3 volts. If you measure the voltage across each bulb, you will read 3 volts, but if you read from the positive side of each light to ground, you will read 12 volts at the first light, 9 volts at the second, etc. All this assuming "
Soundguy
"Each light will actually "see" 3 volts less than the previous, although each light will only be using or dropping 3 volts. If you measure the voltage across each bulb, you will read 3 volts, but if you read from the positive side of each light to ground, you will read 12 volts at the first light, 9 volts at the second, etc. All this assuming "