Jerry/MT
Elite Member
- Joined
- Feb 2, 2008
- Messages
- 3,141
- Location
- North Idaho-The Palouse
- Tractor
- New Holland TD95D, Ford 4610 & Kubota M4500
And of course as volts go down, current goes up. QUOTE]
Can you explain what you mean by this statement?
And of course as volts go down, current goes up. QUOTE]
Can you explain what you mean by this statement?
I think it's possibly the additional current by the inductive load of the starter motor and the interaction of the armature and fields. An inductive load initially has high resistance until the magnetic field is maximumized and then effectively low resistance. If the motor doesn't turn, the load goes to maximum and stays there. Essentially, because of lower voltage, the motor doesn't have sufficient torque to turn the engine at normal speed. Starting current is high for a longer period of time, causing even a slo-blow fuse to pop. If the battery is hot enough to get the starter and engine spinning rapidly, the full torque requirement of the motor is reduced, allowing it to spin at higher rpm but not in a steady high current state. This is a bit of an oversimplification, but I don't think it's too far off.
Nope. Not an oversimplification at all Jim. Right on, except for the use of the term "high resistance" in the second sentence, as the correct term is high impedience which reflects both the resitive and inductive loads. As you note, the high current stays for much too long (due to not turning, or the operator continuing to hold the key) and the fuse heats and blows. The fact that the current is initially slightly less due to the low voltage (as you and others have noted - this is Ohm's Law) is negligible and far outweighed by the substantial length of time. In fact, if the fuse didn't blow, there's a good chance the motor would overheat and fail.
Well, I'm no expert at drawing circuit diagrams, and PowerPoint doesn't seem to supply standard circuit diagram objects to insert, but I did what I could. The attached PDF file is three pages showing the original circuit, the completed alteration to the original circuit, and finally the new starting circuit. There are things missing from the diagram, such as the original fuse, but since you don't touch that part I left it out to keep the drawing simple. The circuit is more complicated than I have shown, but it does show you what you need to know to complete this fix. I tried to use the same wire colors as Jsheds describes where I could, but the white wire was hard to draw on white paper. Let me know if this needs any clarifications and I'll do what I can.
I am having this issue with my DX33. I cannot see any of the pictures y'all have attached. I am using iPhone 6s Plus. We do not have access to high speed internet where we live. I have tried opening with chrome, Safari and opera mini. Any suggestions? Thanks in advance.
Hello. I am trying to purchase the parts you have in your thread to resolve my TC33DA starting problems. Are the 2 parts the only 2 needed? I see in your step #2, it states to run wire thru inline fuse? Is that another part to purchase?The Napa relay I purchased shows part # AR276
I also purchased a plug with 4 wires that plug into the relay part EC23. You do have to make sure the 4 wires are in the position to contact pins 30, 85, 86, 87 (and not 87a)
There are detailed pictures on this site from Jsheds. For those interested a search under TC33DA-Starting problems will furnish good instructions. I basicly followed the instructions that others furnished on this site.
(1) Relay installed under plastic on left side down low in a vacant hole in the steel plate. Attached the inline fuse 30A on the engine side on the same bolt.
(2) Ran the wire from pin 30 thru the inline fuse and attached at the bolt holding the battery positive to the starter.
(3) Ran the wire from pin 85 to ground. I attached to a bolt under the clutch area that holds a hydraulic line. (need a loop end here just like what is needed to attach at the starter.
(4) Unplugged the white plastic connector from the back side of the starter solenoid and cut it off along with a few inches of wire. Connected this white connector to the wire from pin 86 and plugs back to the solenoid.
(5) Take the cut wire that previously went to the solenoid and connect it going to pin 87 .
I saved pictures and instructions on what others posted and printed them out for instructions to follow.