JB4310
Super Member
RonMar said:Power in Watts is = current times voltage(P = I x E) conversely power divided by either current or voltage will = the other remaining value. Your 10KW generator is capable of providing 1/2,the rated output, or 5KW, on each 120V leg. So 120V X 40A breaker value = 4800W. 240V x 40A breaker = 9600W. So 40A per 120V leg is appropriate for a 10KW generator.
OK I got that so far, so I guess that means I can draw the 9600 watts only if it is equally distributed on both the 120 volt legs, if the load goes over the 4800 watts on one leg, then even if the total draw is far less than the 9600, it will still trip the breaker since the two breakers are attached, am I correct to assume this? and is it correct to say that since the generator is rated at 40 amps @ 240 V then it's also 80 amps @ 120 V ? or am I still missing something here. thanks John,