Hydraulic flow pressure force question

   / Hydraulic flow pressure force question #1  

Rio_Grande

Platinum Member
Joined
Dec 11, 2007
Messages
555
Hope I dont get drummed out for this,.... LOL

I have a Gehl CTL 70 Basicly a Mustang MTL 20 Track Loader.

It has a 19.8 GPM pump that runs at a max of approx 2760 psi

I am contemplating making a log splitter for it but I need to determine how much force it would generate with a 4.5 bore cylinder. I think the rod is right at 2 inch of that matters.

I used to have a Excel Sheet that would calculate this for me but no more...

I am conflicted on doing this as I would loose my skid steer for hauling the wood out while someone else runs the splitter... But I am sure I can figure out the logistics of the change if it occurs.

Thanks in advance.
Jeff
 
   / Hydraulic flow pressure force question #2  
43.896 lbs or 21.9 Tons of force. GPM will determin the cycle time.

Extension speed is 4.8 in per sec.
retraction speed is 6.0 in per sec
 
   / Hydraulic flow pressure force question #3  
There are many hydraulic sites to calculate force.
Area = 3.14 r 2 x PSI = force
Force in div 2000 = tons.
21 tons
Craig Clayton
 
   / Hydraulic flow pressure force question
  • Thread Starter
#5  
Thanks Gentelmen, Based on that and recalling previous caculation I have done regarding an engine driven splitter I will stick with it and not loose my skid steer for moving equiptment.

Thanks Fellas..
 
   / Hydraulic flow pressure force question #6  
"I have a Gehl CTL 70 Basicly a Mustang MTL 20 Track Loader."
Actually they are both rebadged Tachiuchi machines.

If you run a fair amount of wood through the splitter keep an eye on the hydraulic oil temperature in the reservoir. Ideally it should stay below ~190ーF. Using the track loader is fine, but it will have more line losses than your typical engine-on-a-splitter setup, which will create more heat.

ISZ
 

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