tsteahr
Gold Member
- Joined
- Jul 22, 2008
- Messages
- 429
- Location
- CT shoreline
- Tractor
- Massey Ferguson GC2410tlb w/ R1 and Rimguard
Because the load rotates, this cause the CoG of the load to be raised higher. Again, you cant get something for nothing. In order for the same amount of weight to be lifted higher, MORE force IS required. Because there is only a given amount of force avaliable at the lift arms (this is determined by the cylinder size, PSI, etc.) the load MUST be reduced in order to be lifted. The lower the toplink's position, the higher the mass is trying to be raised, thus the less weight it can lift.
Back to the W=F x D formula. It really is that simple. The 3PH is only capable of a given aount of work before Hydraulic cylinder size/PSI become the limiting factor. If it is only able to lift 1200lbs to a height of 24", it cannot lift that same mass to a height of 30". The mass MUST be reduce for work to remain the same. If the toplink and the lower links are equal length and parallel, ANY point is only trying to be raised 24", thus it can lift 1200lbs and still be within the avaliable work that the 3PH can do. With a lower/shorter toplink, you are asking that mass to be moved a greater distance with only the same avaliable work. Thus the Mass MUST be reuced. It really doesnt matter how much weight gets transfered or where or what is under compression or what is under tension. The only way to move that 1200lb mass a greater distance is to either increase the work avaliale or shed some weight.
LD1 is exactly right. What he is describing is the Method of Virtual Work. We started talking about that way back in post 27. There is a good condensed but somewhat technical discussion of this subject on Wikipedia if anyone is looking for the math behind it.