As an engineer, I would be very hesitant to use an unknown aluminum I-Beam in this application. However, assuming the dimensions you have given are close to accurate, what you have are beams that conform to a standard 8 inch lightweight I-Beam in dimensions. For an I-Beam, the weight capacity is W=8fS/l where W is the weight capacity, f is the fiber stress (in psi), S is the section modulus (1.9 inch**3 for this beam) and l is the span in inches.
Let's say the beam was steel, with a 20,000 psi allowable fiber stress (typical for something like A36 steel) and the beam is 20 feet (240 inches) long. Then the allowable load is ((8 x 20,000 x 14.2)/240) =9467 lbs. Note that this is a distributed load, so for safety it should be reduced to 1/2, or a little over 4600 lbs. I have no idea what a reasonable allowable fiber stress is for aluminum but I would guess it's a good bit less than for steel. I couldn't immediately find values for aluminum to use for beam calculations but I would hesitate to put a ton of weight on these beams.
Bottom line is you are not going to get much capacity out of these beams. Note that all the above is simplified and assumes the beams are adequately braced to preclude buckling or other out of plane movement.