Phred wrote:
</font><font color="blue" class="small">( This torque is just the product of the force (F) and the distance at which you apply it from the pivot point (R). Conect it up high or on a very long draw bar and you just increased R. )</font>
Yes and no. It's a product, yes, but it's a "cross product" of two vectors. You don't just multiply them together. The magnitude of the torque (it has both magnitude and direction) is equal to R times F times the cosine of the angle between them. That means that if they're both--R and F--pointing in the same direction, the torque is zero. No matter how long the draw bar is, if you hook up at the same level as the pivot point, the torque is zero.
Oh, and if you hook it up BELOW the pivote point instead of ABOVE, then the torque is in the other direction; if you consider the axle to be the pivot point--and the axle's definitely the easiest point to pivot around--then the torque is forcing the front end down, not pulling it up.
It's arbitrary what you consider the "pivot point" to be. If you consider it to be the point of contact between the rear tires and the ground, then you can still tend to lighten the front end by pulling backwards. But it'll only flip, in this case, if you've got REALLY GOOD traction. Most likely the tires will slip before the front end comes up.
Jim