TedLaRue
Gold Member
higgy said:na, it is not the same depending on the size of the ball, the hint is that it is one inch off the table, leaving a cross section that would be roughly d shaped that is contiguous across 360 degrees, That will give you a volume that then can be converted to a weight. When you drilled through the center you eliminated a cylinder of material with a radius on each end.
Calculate it out and get the answer. The size of the sphere is fixed by the 1" hight after removal of the material.
The size of the sphere is not determined by the 1" height. A large diameter hole drilled through a large sphere might leave a 1" tall ring, just as a smaller hole drilled through a smaller sphere leaves a 1" tall ring.
The interesting fact is that the volume of the remaining ring is the same no matter what the size of the original sphere. With a large hole in a large sphere, the thickness of the 1" tall ring would be less because there's less curvature. This compensates for the larger diameter ring.
The volume of a sphere is 4/3 pi r^3, but computing the volume of the remaining ring is not easy.