Weight of water

   / Weight of water #61  
OK, I think the OP needs to just get a bucket and rope and get the water out the old fashion way. All this math is hurting my head.
 
   / Weight of water #62  
Area of a 2.067" ID pipe = (Pii / 4) x 2.067squared
(3.14 / 4) x 4.27 =
0.785 x 4.27 = 3.354 square inches

Area of a 1.315 OD pipe = (Pii / 4) x 1.315squared
(3.14 / 4) x 1.73 =
0.785 x 1.73 = 1.357 square inches

Volume of 2.067 ID x 100' pipe = 2.067 x 100'
2.067 x 1200" = 2480 cubic inches

Volume of 1.357 OD x 100 pipe = 1.357 x 100'
1.357 x 1200" = 1638.4 cubic inches

Subtract 1638.4 cubic inches from 2480 cubic inches = 841.6 cubic inches.

1 gallon displaces 231 cubic inches

841.6 / 231 = 3.64 gallons

1 gallon weighs 8.34 pounds

3.64 gallons x 8.34 pounds = 30.3576 pounds

Someone double check me, please. I've had some Captain Morgan and Dr. Pepper. :drink:

I ran the number you have on my calculator and came up slightly different, so I rechecked by long multiplication by hand and confirmed what my calculator said - 3.35195 square inches. Then I re-did the calculations using pi to 10 digits and got 3.345871574 but since we started with 3 decimal places for pipe diameter, the result should be 3 also, so 3.346 square inches. I went thru and checked the rest and they're all close enough to what I get, it doesn't matter. I end up with a little over 30 pounds as well.

...

OOPS!!! I made a mistake - it's not 30 pounds - it's the 86 pounds.

Here's where the error in the math is:

Volume of 2.067 ID x 100' pipe = 2.067 x 100'
2.067 x 1200" = 2480 cubic inches

The 2.067 is the diameter of the pipe not the area. It should be 3.354 * 1200" = 4024.8 cu inches

Then we have 4025 cu in - 1638 cu in = 2387 cu in = 10.33 gallons

10.33 gal * 8.34 = 86.18 pounds
 
   / Weight of water #63  
Volume of 2.067 ID x 100' pipe = 2.067 x 100'
2.067 x 1200" = 2480 cubic inches

This is where you made your mistake, volume is not diameter x length, it should be area x length. Correct that and you'll get 86.56# (watch your decimals if you don't at least get those two digits of precision).
 
   / Weight of water #64  
OOPS!!! I made a mistake - it's not 30 pounds - it's the 86 pounds.

Here's where the error in the math is:



The 2.067 is the diameter of the pipe not the area. It should be 3.354 * 1200" = 4024.8 cu inches

Then we have 4025 cu in - 1638 cu in = 2387 cu in = 10.33 gallons

10.33 gal * 8.34 = 86.18 pounds

This is where you made your mistake, volume is not diameter x length, it should be area x length. Correct that and you'll get 86.56# (watch your decimals if you don't at least get those two digits of precision).

YES! I see that now. I blame Captain Morgan, but hold the Dr. a bit responsible, as it's just what he ordered. None of it is my fault, of course. :D

Thanks fellers. :thumbsup:

Should we tell the OP or let him undersize his contraption? :confused3:
 
   / Weight of water #65  
The volume of water lifted will be the diameter of the foot valve and total distance to the surface spout. The volume per stroke will be diameter of foot valve and length of stroke.

The inner tubing is not filled with water. It is acting like a pump rod.
 
   / Weight of water #66  
Think of it as a cored pineapple. :licking:

Figure out the volume of the yellow stuff.

88974691-EEC7-4C9E-B884-062B75123B94.jpeg
 

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   / Weight of water #67  
^^^^^
I had that figured out at the first post, but all of the rest is what's hurting my head. Maybe I need some of that Captain Morgan's...
 
   / Weight of water #68  
^^^^^
I had that figured out at the first post, but all of the rest is what's hurting my head. Maybe I need some of that Captain Morgan's...

Hey, you might not get the correct answer, but you won't really care too much. :eek:
 
   / Weight of water #69  
You need to read the thread to answer in a meaningful way. All of us understand water pressure and head but there is a different question being asked.

I read enough to know the questioner didn稚 specify enough to ask a useful question.

Still want to fight?
 
   / Weight of water #70  
If you're using a sucker rod pump with a cylinder at the bottom of the well, you ARE lifting the entire weight of the water above the cylinder, not the static head pressure. The deeper the cylinder the bigger windmill you need to lift the water if the cylinder diameter remains constant.

If your pump can not exceed the static head pressure then it can not lift the water.
 

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