LD1
Epic Contributor
Let me start by saying that there are way too many variables to figure it to a tee without a lot of hassle. Ground condition, tire type, inflation pressure, F/R weight split, etc. It would have helped if you had said what type of tire you plan on using, R-1, R-3, or R-4's. That said, I have come up with a formula that works reasonabally well for comparitive purposes in average conditions.
I have found that in average conditions for most tires that the contact patch length is about 3/4 of the rim diameter and the width is about 1" less than the tire measurment.
So for the B3030 with AG's and MMM weighs about 2734 lbs and the tires are
F 7-12
R 12.4-16
Front (.75 x 12)= 9 multiplied by width (7-1)=6......9 x 6= 54 sq in
Rear (.75 x 16) x (12.4-1) = 136.8 sq in
(54 x 2) + (136.8 x 2) = 381.6sq in
2734/381.6 = 7.16 psi ground pressure
The JD weighs 4070 lbs (assuming about 500lbs for MMM as I could not find a spec) and it has 7-14 fronts and 11.2-24 rears
(.75 x 14) x (7-1)= 63 sq in front
(.75 x 24) x (11.2-1) = 183.6 sq in rear
(63 x 2) + (183.6 x 2) = 493.2 sq in
4070/493.2= 8.25psi ground pressure.
Like I said, there are a lot of variables, but this is a good way to compair tire sizes, and can be applied to r-4's and turfs. But keep in mind that the ag psi's that I calculated above assume that you are burrying the bar tread in the ground so that the body of the tire is contacting the ground.
I have found that in average conditions for most tires that the contact patch length is about 3/4 of the rim diameter and the width is about 1" less than the tire measurment.
So for the B3030 with AG's and MMM weighs about 2734 lbs and the tires are
F 7-12
R 12.4-16
Front (.75 x 12)= 9 multiplied by width (7-1)=6......9 x 6= 54 sq in
Rear (.75 x 16) x (12.4-1) = 136.8 sq in
(54 x 2) + (136.8 x 2) = 381.6sq in
2734/381.6 = 7.16 psi ground pressure
The JD weighs 4070 lbs (assuming about 500lbs for MMM as I could not find a spec) and it has 7-14 fronts and 11.2-24 rears
(.75 x 14) x (7-1)= 63 sq in front
(.75 x 24) x (11.2-1) = 183.6 sq in rear
(63 x 2) + (183.6 x 2) = 493.2 sq in
4070/493.2= 8.25psi ground pressure.
Like I said, there are a lot of variables, but this is a good way to compair tire sizes, and can be applied to r-4's and turfs. But keep in mind that the ag psi's that I calculated above assume that you are burrying the bar tread in the ground so that the body of the tire is contacting the ground.