Paddy
Veteran Member
MossRoad,
Ok I read the site. Two things are kinda funny here. First, your just quoting another message board and second, if you read the post closely, he stating all the No-Fly camp is changing the the problem from "will it Fly" based on the original problem to "can we make a MCB that can counter act the force of the plane" He says , "sure" but that was not the original problem.
Then you go on to say;
((Now I could say "what you fail to understand is..." but I won't. But I will say, open your mind to the possibility that if you could make a conveyor that would move EXACTLY at the same speed as the airplane, but in the opposite direction, it will keep accellerating to counter the planes accelleration in the opposite direction, preventing the plane from moving.))
I say; If they both have the same velocity, they both have the same acceleration. There is no countering here, just matching. You can have very low acceleration and still have very high velicity. not sure your point
But hey let's start with good basic problem solving skills that they taught us in engineering school, sketch/vectors and assumptions. (I hope we don't have to make to many assumptions because that could get us all turned around!)
Problem Statement: (I always hated this part, re-right the problem!)
---------------x-------------x--------------x-------------x--------x----
a plane is standing on a movable runway( something like a conveyor).as the plane moves the conveyor moves but in the opposite direction.the conveyor has a system that tracks the speed of the plane and matches it exactly in the opposite direction. the question is will it fly?
------x--------x--------x---------x----------x----------x---------x-----
Sketct time;
I'm not very good using sketch tools so I will try to use a mental description I think we can all imagine and work with. let's use some sort of reference like a foot ball field's lines.
Ok, let's start with the first statement about "a plane standing on a movable runway". Ok, we got two objects to place in our sketch. Let's put a dot on the convayer and a dot on the plane and put them on the 50 yard line. I think these dots might help to keep this all straight
Assumption 1; the plane isn't really standing. It doesn't have legs, It's probally was meant to be resting. ie, not moving at T= zero
OK, now let's get that next statemnet we need to get in our sketch. "as the plane moves the conveyor moves but in the opposite direction." We need to place some velocity vectors in our sketch. Let's draw an arrow ponting left on the convayers dot and lable it, Vc (velocity convayer). same for the plane now, but in the oposite direction. This would mean an arrow pointing right labled, Vp.
Assumption 2; We don't need acceleration vectors because of the next statement, "the conveyor has a system that tracks the speed of the plane and matches it exactly in the opposite direction.". That means If |Vc| = |Vp| then |Ac| = |Ap|. The |Xx| just is way to compare values with out direction
Assumption 3; Speed and velocity can be used interchangabley. The difference between speed and velocity is V has direction and the problem has already stated "in oposite directions"
Last part of the sketch is to make sure the vectors, Vc and Vp are the same length because, ""the conveyor has a system that tracks the speed of the plane and matches it exactly in the opposite direction.". Let's go a head and note in the sketch, |Vc| = |Vp| just in case someone misses that, Vc is a negitive value because it's going left and Vp is positive...well I think you got it.
Summary; sketch of plane with dot/vector pointing R and lined up on 50 yard line and convayer with dot/vector pointing L
Assuption 4; Plane is a realist type with normal speeds, wheels and bearings ( not rockets or teflon!!)
Assuption 5; Convayer can match the velocity and acceleration of this normal plane (No magic needed here because the planes Vp and Ap are not so impressive. The group of engineers witnessing estimate this weeny plane would require a full min to take off on a good day) As stated in the problem, matches planes speed, carefully note that does not mean match plane thrust or wheel rotational speed or teflon coated rocket do do
Assuption 6; Since bearing friction is such a small percentage compared to wind drag, it can be ignored. (Sea planes endure much higher landing gear drag/resistance than wheeled aircraft and they appear to take off just fine, just with a longer take off distance and time) If you don't belive this take your ele drill and chuck up a 4" dia wheel some or another and spin a small trailer wheel. Once you get her spinning, you won't find it takes much force to hold the drill. If you still don't beleive me ask your self, if I installed two extra wheels on a plane, would it prevent it from rolling? Because that is what the convayer is doing if the friction in porportion to wheel speed, doubling the wheel friction vis double speed. Double speed of the wheels might be diff to understand if you can't get "two cars moving at 30 mi/hr, one heading east and one heading west, How fast are being seperated by?" question. Hint, answer is 60 mi/hr
Time for tables. (I always hated these too)
Time (Sec)----Vc-----Vp
0----------- 0------ 0
1----------- -1----- 1
2---------- -1.1---1.1
Time out here! Now let's go back at look at that sketch and the problem. OK, the speed of the plane is being matched, good. The plane is moving as stated in the problem The dot on the plane is at the 52 yard line and the Dot on the convayer is on the 48 yard line. Ok..please don't make me complete this table! Thanks, I just jump ahead 30 sec
32----------- -42-- 42
42---------- -50-- 50
Stop! we left the foot ball field and were heading for the goal posts at a high rate of speed.
I interviewed the pilot after this crazy stunt and he told me it felt a bit funny. like he had a bit more drag and if wasn't for those darn goal post would reached lift off speed.
Ok I read the site. Two things are kinda funny here. First, your just quoting another message board and second, if you read the post closely, he stating all the No-Fly camp is changing the the problem from "will it Fly" based on the original problem to "can we make a MCB that can counter act the force of the plane" He says , "sure" but that was not the original problem.
Then you go on to say;
((Now I could say "what you fail to understand is..." but I won't. But I will say, open your mind to the possibility that if you could make a conveyor that would move EXACTLY at the same speed as the airplane, but in the opposite direction, it will keep accellerating to counter the planes accelleration in the opposite direction, preventing the plane from moving.))
I say; If they both have the same velocity, they both have the same acceleration. There is no countering here, just matching. You can have very low acceleration and still have very high velicity. not sure your point
But hey let's start with good basic problem solving skills that they taught us in engineering school, sketch/vectors and assumptions. (I hope we don't have to make to many assumptions because that could get us all turned around!)
Problem Statement: (I always hated this part, re-right the problem!)
---------------x-------------x--------------x-------------x--------x----
a plane is standing on a movable runway( something like a conveyor).as the plane moves the conveyor moves but in the opposite direction.the conveyor has a system that tracks the speed of the plane and matches it exactly in the opposite direction. the question is will it fly?
------x--------x--------x---------x----------x----------x---------x-----
Sketct time;
I'm not very good using sketch tools so I will try to use a mental description I think we can all imagine and work with. let's use some sort of reference like a foot ball field's lines.
Ok, let's start with the first statement about "a plane standing on a movable runway". Ok, we got two objects to place in our sketch. Let's put a dot on the convayer and a dot on the plane and put them on the 50 yard line. I think these dots might help to keep this all straight
Assumption 1; the plane isn't really standing. It doesn't have legs, It's probally was meant to be resting. ie, not moving at T= zero
OK, now let's get that next statemnet we need to get in our sketch. "as the plane moves the conveyor moves but in the opposite direction." We need to place some velocity vectors in our sketch. Let's draw an arrow ponting left on the convayers dot and lable it, Vc (velocity convayer). same for the plane now, but in the oposite direction. This would mean an arrow pointing right labled, Vp.
Assumption 2; We don't need acceleration vectors because of the next statement, "the conveyor has a system that tracks the speed of the plane and matches it exactly in the opposite direction.". That means If |Vc| = |Vp| then |Ac| = |Ap|. The |Xx| just is way to compare values with out direction
Assumption 3; Speed and velocity can be used interchangabley. The difference between speed and velocity is V has direction and the problem has already stated "in oposite directions"
Last part of the sketch is to make sure the vectors, Vc and Vp are the same length because, ""the conveyor has a system that tracks the speed of the plane and matches it exactly in the opposite direction.". Let's go a head and note in the sketch, |Vc| = |Vp| just in case someone misses that, Vc is a negitive value because it's going left and Vp is positive...well I think you got it.
Summary; sketch of plane with dot/vector pointing R and lined up on 50 yard line and convayer with dot/vector pointing L
Assuption 4; Plane is a realist type with normal speeds, wheels and bearings ( not rockets or teflon!!)
Assuption 5; Convayer can match the velocity and acceleration of this normal plane (No magic needed here because the planes Vp and Ap are not so impressive. The group of engineers witnessing estimate this weeny plane would require a full min to take off on a good day) As stated in the problem, matches planes speed, carefully note that does not mean match plane thrust or wheel rotational speed or teflon coated rocket do do
Assuption 6; Since bearing friction is such a small percentage compared to wind drag, it can be ignored. (Sea planes endure much higher landing gear drag/resistance than wheeled aircraft and they appear to take off just fine, just with a longer take off distance and time) If you don't belive this take your ele drill and chuck up a 4" dia wheel some or another and spin a small trailer wheel. Once you get her spinning, you won't find it takes much force to hold the drill. If you still don't beleive me ask your self, if I installed two extra wheels on a plane, would it prevent it from rolling? Because that is what the convayer is doing if the friction in porportion to wheel speed, doubling the wheel friction vis double speed. Double speed of the wheels might be diff to understand if you can't get "two cars moving at 30 mi/hr, one heading east and one heading west, How fast are being seperated by?" question. Hint, answer is 60 mi/hr
Time for tables. (I always hated these too)
Time (Sec)----Vc-----Vp
0----------- 0------ 0
1----------- -1----- 1
2---------- -1.1---1.1
Time out here! Now let's go back at look at that sketch and the problem. OK, the speed of the plane is being matched, good. The plane is moving as stated in the problem The dot on the plane is at the 52 yard line and the Dot on the convayer is on the 48 yard line. Ok..please don't make me complete this table! Thanks, I just jump ahead 30 sec
32----------- -42-- 42
42---------- -50-- 50
Stop! we left the foot ball field and were heading for the goal posts at a high rate of speed.
I interviewed the pilot after this crazy stunt and he told me it felt a bit funny. like he had a bit more drag and if wasn't for those darn goal post would reached lift off speed.
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