You seem to have some knowledge so I may take this as an opportunity to learn something...
But where are you arriving at your numbers? Or what formulas are you using. This is a little outside my wheelhouse....and lets face it.....this design just isnt common at all in modern design.....
But the closest formulas I am coming up with is the formula for tension in the bottom member of a truss.....which is the bending moment divided by depth.
And in this case.....with 3000# midspan of a 18' beam....(PL)/4 gives me 13,500 bending moment And the total structure with a 6" standoff is 1' total depth. So 13,500 / 1 = 13,500# of tension?
But you are saying a 15x of load would be 45,000# of tension?
Im not trying to dispute your info....as this is kinda a peculiar design and the ONLY time I have ever seen such a design is to strengthen the y-axis on overhead cranes....just trying to learn the correct method of determining tension is this unusual design.
Yesterday when I posted that I just did math assuming the bridge deflected by half of an inch vertically, and considered what that does to the tension rod.
Once again a caveat - I'm not an engineer, don't trust these numbers. They make sense to me right now, but someone will probably properly come along and educate me.
Today while writing this up, I decided to see what the actual math involved is. Note that this is still simplistic because as soon as the bridge deflects at all, the angles change infinitesimally so the math changes. For rough purposes though, we can see what the tension is in the rod instantaneously before any deflection occurs (deflection
will occur; the tension rod is there to reduce it; you literally can't eliminate it entirely with metal).
OK? Ok, let's go.
Consider if you have a weight hanging from a rod, vertically. Any vertical deflection will be transmitted directly into that rod, 1:1, no mechanical advantage. Just like if you're winching a load without any snatch block.
What does a snatch block do? It allows you to pull twice as much cable per unit of work done - pulling 2' of cable to move the load 1' - which gives you a 100% mechanical advantage.
Now consider if you have a triangle under the bridge, with a tension rod as the diagonal. The slightest deflection of the center of the bridge will require a lengthening of the tension rod, commensurate with the ratio of the length of the tension rod (the hypotenuse of the triangle) to the height of the triangle, or in math, the cosecant of the angle that the rod forms at the end of the bridge. Bigger angle, smaller ratio, and "better" mechanical (closer to 1:1). Smaller angle, "worse" mechanically (larger penalty).
To illustrate consider three bridges with different standoff heights for different angles of their tension rod:
In this picture, the big black parts are the bridges. The blue are the stand-offs for the tension rod, and the reds are the tension rods.
In the first part, the tension rod is at a 45° angle, and any lengthening of the blue standoff (ie, deflection of the bridge in the middle) will require ~1.4x that deflection lengthening of the tension rod - one millimeter deflection is echoed in 1.4mm of tension rod. The deflection is causing a 1.4x stretch in the tension rod; 1000# causing deflection is effectively 1400# tension on that rod.
The second bridge shows a 30° angled tension rod. Because that angle is lesser, every bit of deflection is reflected double in the tension rod; 1mm deflection requires 2mm of rod stretch. 1000# deflection results in 2000# tension in the rod.
The third bridge shows a 10° angled tension rod (with a ~21" tall standoff! 10° isn't much but over 10' it's still almost two feet tall!). The ratio rapidly gets bigger and bigger as the angle lessens - here we have a 5.75x multiplier! A 1000# load is reflected as 5750# tension on the rod!
The smaller the angle gets, the harder any deflection is pulling on that rod, because the slighest deflection causes a much larger lengthening of the rod.
Basically, if you want to stretch a rod, build a really shallow triangle under a bridge and put a weight on the bridge. If you don't have enough weight, make the triangle even thinner so that you have a greater mechanical advantage on that rod. Of course, to
strengthen a bridge, we want to reduce the mechanical advantage on the rod, which requires a taller triangle. You can only get so tall, so at some point you need to use a thicker rod to resist the deflection. Also, you have four such rods, so each one only needs to carry on fourth of the tension, though I'd prefer to spec it so that you're way overkill on the rods so that you don't have one break - because if one breaks, its mate on the other side of the triangle will probably pull the standoff over, so suddenly you only have two rods left on the other side of the bridge... and if the bridge load broke one out of four and you now only have two, you're likely to lose the other two as well. Drive fast.