Soundguy
Old Timer
- Joined
- Mar 11, 2002
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- RK 55HC,ym1700, NH7610S, Ford 8N, 2N, NAA, 660, 850 x2, 541, 950, 941D, 951, 2000, 3000, 4000, 4600, 5000, 740, IH 'C' 'H', CUB, John Deere 'B', allis 'G', case VAC
</font><font color="blue" class="small">( This will only tell me if I've got enough "room" in that particular circuit. The alternator may not have enough "umph" (that's a technical term... ) to drive all of the circuits that I have access to (or even "all" of one circuit). If, as has been suggested in other posts, I only have a 10 amp alternator, this theory wouldn't hold true...
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Not exactly... just beacuse you have a 10 amp alternator doesn't mean that the 'theory' is wrong.. just means that while running that load, your storage battery is discharging the the remaining amps in excess of what the alternator can handle... just like it would do if you were not running, but had the lights on. Duration at that load would be determined by the amp hour rating of your battery, at that load.
It is quite possible to have a fused circuit that has a fuse rating higher than the max output of the alternator.
Soundguy
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Not exactly... just beacuse you have a 10 amp alternator doesn't mean that the 'theory' is wrong.. just means that while running that load, your storage battery is discharging the the remaining amps in excess of what the alternator can handle... just like it would do if you were not running, but had the lights on. Duration at that load would be determined by the amp hour rating of your battery, at that load.
It is quite possible to have a fused circuit that has a fuse rating higher than the max output of the alternator.
Soundguy