Kernopelli said:
Howdy neighbor, this may be a bit of a headache to actually do.....but.
Once you find a motor and see its rated RPMs at given flow I think if you go to Baum Hydraulics calculators and use the vehicle speed calculator and use the winch drum diameter it will give you ft/min. They also have a calculator that figures hyd. motor HP.
Baum Hydraulics :: Spec Calculator then use this to convert HP to torque
Horsepower vs. Torque BTW: TractorData.com says the 8N engine was rated at 92 LBS/FT at full throttle.
Well Howdy Neighbor! Good to see someone from the "neighborhood" on here!
I wonder if there is any way to calculate (I know there is, but I'm no engineer) what the torque output of the PTO would be at the 92ft/lbs engine? I'm sure it would be substantially higher due to the gear reduction in the transmission. Let's see here...
If I'm remembering correctly, on the 8N, 1550 engine rpm equates to 536 PTO rpm, for a ratio of .346.
92ft/lbs divided by .346= 265.9 ft/lbs at the PTO... so, figure in some mechanical losses, which would put it probably in the neighborhood of 260 ft/lbs at the PTO, at full power.
Sound logical? I don't think I need that much torque, since the torque available at idle is adequate enough to literally pull the 8N completely over.
I wish Piccar would email me back, all I really need is how much input torque is required to get, let's say, a 10000# line pull. Then I could use that number to match up to the motor I would need, and life would be easy.
I'm probably going to leave it PTO powered anyway, so all of this is moot

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