LogSplitter No power on stroke or return

[J_J]

Your switch over on that 2 stage pump is about 600 psi.

Here are some details for your pump.

http://www.northerntool.com/images/downloads/manuals/1056.pdf

Look at first page.

Min HP to run that pump is about 8 HP according the chart.

I think you are running out of HP with that 5 HP engine.

Since the second stage on that pump is about 3.97 cu in, and at 3000 psi, Hp required is 8.

You can achieve 2000 psi with 5 HP and a cu in of 3.97.

So , what is happening is that when the pump gets to 2000 psi, it will stall the pump. If you had 8 HP, The pump is capable of producing up to 3000 psi, but the max relief on that valve is 2750 psi.

When you get your gage, check the relief.

You need to re-engine the splitter or replace the pump for a smaller GPM.

 

[wdchyd]

wdchyd,

Just saw that you were selected as Member of the Month.

Congratulations, you contribute a lot to this forum and others, and we all appreciate it very much.

Thanx JJ

I do try to help but sometimes difficult without actually laying eyes on the projects

One thing I've learned in hydraulics.......trust only what you can see, not what others say they see

 

[finishsuper]

OK, was wondering on the point. The guy that I bought it from stated that he originally had a 12hp motor on it, but it died and that he replaced it with the 5hp Honda (cost as the main deciding factor). He didn't say how much he used it with the 5hp, but that if I ran it "wide open", it should be ok.

Looks like the recommendation for the 5hp is either the 1012 or the 1053. Any experienced recommendation? From what calculations I've seen, this should still generate enough pressure to end up with around a 20 tonner. Does this sound right? I just need something that will split the average, everyday, run of the mill firewood, with the occasional knotty piece of you-know-what.

Is there a market to sell the 1056 pump, even if deeply discounted? Ebay or maybe someone here could use it?

Once again, thanks for the advice and expertise. It is greatly appreciated.

 

[J_J]

The pressure relief on that valve can be set as high as 2750 psi, so if using a 4 in cyl with a 2 in shaft, you will have a push force of 34,557, or 17.27 ton. That should do most of your splitting.

The GPM only determines the splitting speed. You will be a little slower.

You should be able to sell the pump.

 

[finishsuper]

Thanks, that should be plenty of force for what I'm doing with- mainly saving my back (and my father's) from swinging the maul and sledge hammer so much. I don't have a problem kicking some of the gnarly stuff over the bank, if I need to.

I posted a question on the Northern site about the pumps: 1012 & 1053

On the 1053 description, it says that minimum horsepower is 6HP, but on the product manual (same pdf file you provided for me) the minimum is 5HP. So....... which is right? Am I just better off to go with the smaller pump and be done with it?

 

[J_J]

All the pumps will supply the same power/pressure. The smaller pumps will be slower.

 

[finishsuper]

I stuck a question up on the Northern site about the discrepancy between the product description and the product manual (also listed in the product description). Since there is a holiday tomorrow, I will wait and see what kind of answer I get, if any, and then probably go with the 1053.

Will try to get the pressure gauge installed with the new pump and then will report back the results. Thanks again for the insight and information. (The woodpile is not thankful though....... it just sits there next to the wood splitter scared......)

 

[J_J]

If you know your displacement and GPM required, there are formula's to compute the required HP.

Surplus Center - Hydraulic Cylinders Pumps Motors

Select Tech help top left.

Left side of page, look for Calculators

Select pump displacement and HP.

Fill in the blocks with your pumps GPM and pressure and you will see the required HP .

 

[finishsuper]

Excellent! I think I'm going to go with the 1012, and then hang on to the 1056 pump. If the speed is too slow (I doubt it), or the power is not enough (I doubt it), I will look for an 8hp motor and use the 1056 pump. If I do have to upgrade, then I can bundle the 5hp motor with the 1012 pump (a known compatible combo) and sell them as a unit.

Buying the 1012 seems like the most cost effective solution, should give me an operational splitter and I can evaluate the adequacy based upon it's performance on what I am splitting (time and effort).

Once again, I appreciate the information and help working through the thought process. Thanks!

 

[wdchyd]

All the pumps will supply the same power/pressure. The smaller pumps will be slower.

Glad the OP'r found his problem.....would've been nice to know a SMALL detail about changing out the engine to less horsepower....

Don't forget JJ that hydraulics has no power of it's own....hydraulics is just power transmission from one source to another......a pump is just one link in a chain of events