J_J
Super Star Member
- Joined
- Sep 6, 2003
- Messages
- 18,952
- Location
- JACKSONVILLE, FL
- Tractor
- Power-Trac 1445, KUBOTA B-9200HST
Re: PT-425 PROS & cons??
OK, I will try and see if this works. If the wheel width is 54 in, and if you use the formula for a circle, the distance the outside wheel travels is 339 in, or 28.25 ft. if you increase the wheel width to 59 in. The distance that the outside wheel travels is 370.25 in, or 30.87 ft.
I computed the circumference using 54 in as the first radius, and 59 in as the second radius. If this not correct, some one please correct.
Circle
Area = πr2
Circumference=2πr
r = radius
KentT said:The rate of turn is caused by the maximum articulation of the tractor, which remains unchanged.
OK, I will try and see if this works. If the wheel width is 54 in, and if you use the formula for a circle, the distance the outside wheel travels is 339 in, or 28.25 ft. if you increase the wheel width to 59 in. The distance that the outside wheel travels is 370.25 in, or 30.87 ft.
I computed the circumference using 54 in as the first radius, and 59 in as the second radius. If this not correct, some one please correct.
Circle
Area = πr2
Circumference=2πr
r = radius