LD1
Epic Contributor
The force of a hydraulic cylinder on an angle is the sin of the angle times the force of the cylinder.
Lets say at ground level, the cylinder to boom angle is 30 degrees and you have a pair of 2" bore cylinders operating at 2500psi.
Each cylinder can push straight with 7850# of force, or 15,700# combined between them. But account for the 30degree angle.
Sine30 = 0.5
15,700 * 0.5 = 7850# of force to lift.
AS you near the top, the angle becomes much less than the 30 degrees you started with. Dont know specifics and all loaders are different, but lets call it 10 degrees at the top.
Sin 10 = 0.17
15,700 * 0.17 = 2669# of force to lift with
ALOT less force. ITs all about the angles and geometry.
Lets say at ground level, the cylinder to boom angle is 30 degrees and you have a pair of 2" bore cylinders operating at 2500psi.
Each cylinder can push straight with 7850# of force, or 15,700# combined between them. But account for the 30degree angle.
Sine30 = 0.5
15,700 * 0.5 = 7850# of force to lift.
AS you near the top, the angle becomes much less than the 30 degrees you started with. Dont know specifics and all loaders are different, but lets call it 10 degrees at the top.
Sin 10 = 0.17
15,700 * 0.17 = 2669# of force to lift with
ALOT less force. ITs all about the angles and geometry.