- Nov 17, 2009
- Beloit, KS
- Kubota B9200 HSTD and Mahindra 3015
It becomes a very complex computation to calculate, because you are taking a linear force and trying to convert it to a rotational force.No we arent.
I am talking about the distance from where the cylinder hooks to the bucket in relation to the pivot.
Where the 4-bar link attaches to the bucket is ALOT closer to the bucket/boom pivot than the direct pin.
If the bucket was only dumped half way.....the direct pin would have alot greater mechanical advantage.
At full dump or full curl the 4-bar would have the advantage. The lines would cross somewhere in between. It becomes a very complex computation to calculate, because you are taking a linear force and trying to convert it to a rotational force.
Not dissimilar to a piston, rod, and crankshaft in the engine. If the crankshaft is at perfect 180 degrees....you could put as much force on the piston as you wanted and it wont move. IF the crank were at 90 degrees....a pound of force equals way more rotational force going into the crank than say a pound of force on the piston if the crank were at 20 degrees.
And the above is infinitely variable. FULL dump is gonna have a different equation/value than say 2 degrees less than full dump.
Actually its just a matter of using the perpendicular distance from the line of force to the pivot pin. That times the force being applied computes to torque. (rotational force)