fiddler kelly said:
If I set that up for a ram to dump it what size ram would I need and are there certain guidlines for calculating the size of ram you would need.
I'll make an attempt at answering this question.
You need to know four things...
1) the upward force needed to dump the load.
2) the rise of the ram (the difference in height between the top of the ram and the bottom of the ram)
3) the length of the ram measured from pin to pin.
4) the hydraulic pressure of the system that you are using to power the ram.
I start by figuring the force needed to dump the load is equal to the weight of the load itself. This is a rough guess since the weight in front of the ram attachment point is different from the weight behind it and both are altogether different from the weight behind the hinge point of the dump bed. But, it's the rough guess number that I have started with.
The needed force of ram is calculated by multiplying the actual length of the ram as measured from pin to pin times the force needed to dump the load divided by the rise.
If you are dumping a 2000 pound load with a 24 inch ram with a 6 inch rise, your force needed is 24 X 2000 divided by 6 = 8,000 pounds of force.
The cross-sectional area of a ram that will produce 8,000 pounds of force is calculated by dividing the needed force by the system pressure. If you have a 1500 psi system, 8,000/1500 = 5.33 square inches.
To calculate the ram size, divide the cross sectional area by 3.14159 (pi) and then take the square root of the result. Multiply the answer by two to get the ram diameter. 5.33/3.14159 = 1.69 The square root of 1.69 is 1.3; 1.3 X 2 = 2.6 inches.
In this scenario you'd either need a three inch ram (since they don't make 2.6 inch rams) or you'd need more pressure or a bigger rise to make a 2 inch ram work.