LD1
Epic Contributor
I am planning on turning a flat bed into a dump bed with a normal cylinder lift (not a scissor) and was just pondering the formula for the calculation of cylinder force mounted on an angle and hoped you guys might be able to clear some things up.
According to the formula you take the sin of the angle x the cylinder force and you get the vertical lift force of of the cylinder. What I don't inderstand is why this formula is the correct one when to me the numbers just dont add up.
Example: I plan on using a 3.5" x 30" cylinder with a 3000psi pump which = 28,800lbs force. the cylinder is 34" retracted length and I plan on the base being 16" below the rod pivot.
Sin 16/34= ~28* according to the formula that would = 13520lbs lift.
But the sin of 62* (the other angle to equate to rearward push) x 28800 = 25428lbs. How can a cylinder with a force of 28800lbs create a total of about 39000lbs force??? What am I missing.
Wouldn't it be better to use force vectors. where 16" is the vertical leg of the triangle, 34 is the hypotenuse, which would make the horizontal leg = 30
30+16=46
16/46 x 28800= 10017lbs vertical lift and
30/46 x 28800= 18782lbs horizontal force
Which totals 28800lbs
I have attached a rough diagram
What am I missing????
According to the formula you take the sin of the angle x the cylinder force and you get the vertical lift force of of the cylinder. What I don't inderstand is why this formula is the correct one when to me the numbers just dont add up.
Example: I plan on using a 3.5" x 30" cylinder with a 3000psi pump which = 28,800lbs force. the cylinder is 34" retracted length and I plan on the base being 16" below the rod pivot.
Sin 16/34= ~28* according to the formula that would = 13520lbs lift.
But the sin of 62* (the other angle to equate to rearward push) x 28800 = 25428lbs. How can a cylinder with a force of 28800lbs create a total of about 39000lbs force??? What am I missing.
Wouldn't it be better to use force vectors. where 16" is the vertical leg of the triangle, 34 is the hypotenuse, which would make the horizontal leg = 30
30+16=46
16/46 x 28800= 10017lbs vertical lift and
30/46 x 28800= 18782lbs horizontal force
Which totals 28800lbs
I have attached a rough diagram
What am I missing????