OK I tested my tractor relief pressure. By curling the bucket until it bottomed, my system went up to 2100psi. So, this is what the relief is set to in the loader control valve. Now, if I add the power beyond and have a lower setting on the new control valve, attached through the power beyond port, then my system pressure relief will be set to the new valves relief setting. Correct?
So, that means I need to set the PB valve relief to 2100 psi also. Correct?
Thanks aczlan, that is good advice! But, I may be limited to keeping the relief pressure high in order to keep from loosing power on my loader. Assuming of course, that my understanding of the pressure relief is correct. If I start shearing a lot of bolts then I may increase the bolt grade at risk to my box, or lower the relief while using the auger and raise it back up when not in use if my loader is too weak.
Now that I know my pressure, target torque, and rpm for the auger I should be able to match it pretty closely with the gearbox and motor. Assuming my calculations are correct on the torque required to shear the bolt, I should be able to avoid shearing by learning the engine load/rpm, and lifting the auger when it becomes bogged down. With the auger attached to my loader, and fed through the PB port, when I lift the loader, it will reduce power to the auger at the same time the loader is lifting, which should avoid shearing the bolt. Again, that is, if I am understanding the hydraulics correctly.
The required torque to shear the bolt I am using just as a guide to help me determine the minimum power I need in a Hyd motor. Hopefully I will be able to prevent shearing, but I want it to be strong enough to do so.