wood furnace capacity
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gwdixon
Elite Member
OK, let's do it the simple way.
Fill the firebox full of water and then pour the water into 1 cu. ft. boxes.
OR...fill gallon jugs with the water. 1 gallon = 8.35 lbs, 1 cu. ft. water = 62.4 lbs. So about 7.5 gallons = 1 cu. ft.
See how simple it is. :drink: :cool2:
Fill the firebox full of water and then pour the water into 1 cu. ft. boxes.
OR...fill gallon jugs with the water. 1 gallon = 8.35 lbs, 1 cu. ft. water = 62.4 lbs. So about 7.5 gallons = 1 cu. ft.
See how simple it is. :drink: :cool2:
gwdixon
Elite Member
Really though, if LD1's picture is correct, just figure the volume of a rectangular prism. Fudge a little wider on the bottom so the rectangle fits the end with a little over in some areas and a little under in others. Then it is just L x W x H. That will be plenty close enough.
There are so many other variables as to type of wood, dryness, draft, etc. that the burn rate and btu output will only be a gross approximation at best.
There are so many other variables as to type of wood, dryness, draft, etc. that the burn rate and btu output will only be a gross approximation at best.
When you've burn't wood for 37 years and its all been a variety of oak and crappy maple, you can get a pretty good idea. What will be interesting is the different draft parameters with the new chimney with 6" diameter metal pipe and insulated as opposed to the old 7x11 clay tile uninsulated. Heat for heat i'm hoping the furnace will out heat the hooded/ducted wood stove with the same amount of wood. Doesn't seem to be a whole lot of user info on this particular furnace.
Larro Darro
Elite Member
Are each of the seven sides the same size, and just have different angles? If so, and if you can measure from top to bottom at the highest point, and from side to side at the widest point, you can figure it without the angles.
But if each side is 9" and it is 18" at the widest point, you can divide the bottom into two triangles and a rectangle. You have a 9" side and a 4.5" side to the triangles. To get the third side you use A squared + B squared = C squared. Or in this case 81= ??+20.25. So the third side is the square root of 60.75, or 7.7942288. We will round that off to 7.8" since we are talking firewood here.
Then you use Area = 1/2 X Base X Height. That is 1/2 X 7.8 X 4.5 = 17.55 square". There are two of these triangles, plus a 9" X 7.8" rectangle {70.2 square"} So the area of the bottom half is 105.3 square". Just multiply that by the depth and you will have just under half of the volume. Simple.
But if each side is 9" and it is 18" at the widest point, you can divide the bottom into two triangles and a rectangle. You have a 9" side and a 4.5" side to the triangles. To get the third side you use A squared + B squared = C squared. Or in this case 81= ??+20.25. So the third side is the square root of 60.75, or 7.7942288. We will round that off to 7.8" since we are talking firewood here.
Then you use Area = 1/2 X Base X Height. That is 1/2 X 7.8 X 4.5 = 17.55 square". There are two of these triangles, plus a 9" X 7.8" rectangle {70.2 square"} So the area of the bottom half is 105.3 square". Just multiply that by the depth and you will have just under half of the volume. Simple.
vtsnowedin
Elite Member
It doesn't matter , the firebox is way too small for any house north of Florida. You can build a small fire in a big furnace but you can't build a big fire in a small one.
I know. These stove and furnace companies can get mighty loose on their specifications as far as heat output capacity. I think they tabulate from a house in South Carolina some place. Allegedly this particular furnace puts out more captured heat than from their over 4 cu ft furnace that does not have this technology. I guess the proof is in the pudding.