Yep... look at Volts x amps/745 for more accurate Hp number.Also, air compressor manufacturers have been caught stretching the truth. My Cambell Hausfeld 6 Horsepower / 60 Gallon compressor is actually only 3.4 Horsepower. Beware of Lies!
it was probably 6HP. PEAK. NOT Average.. like when the motor is stopped very quickly after it gets to full speed!..Companies sure know how to troll for Suckers. Sears also nailed me on a 6hp Shop Vac about 20 years ago. It couldn't have been over a 1hp. Still using it with a "Dust Deputy" in the garage.
if someone wants to calculate the kinetic energy of a motor running a 3450 rpm and has a 10 lb. rotor, here's the formula.. Kinetic energy is directly proportional to the mass of the object and to the square of its velocity: K.E. = 1/2 m v2. If the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared. Kinetic energy is usually measured in units of Joules (J); one Joule is equal to 1 kg m2 / s2." look at Volts x amps/745 for more accurate Hp number"
Mark, a MINOR "nit pick" - 1 electrical horsepower is 745.7 watts :laughing:
Also, using that formula only tells you how much horsepower you're INPUTTING; one example - the 5 horse industrial compressor I linked to previously in this thread, uses 21.5 amps @ 240 volts: so it's INPUT power works out to just over 6.9 horsepower. Works out to just over 72% efficiency, IF that Baldor motor's only putting out a REAL 5 horsepower.
And no, I'm NOT gonna hook it up to a rope/pulley/weight and see if it can lift a 550 lb weight more than 5 feet per second :laughing:
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radios1 - I've seen little 120 volt vertical "roll-around" compressors marked 6 horsepower; pretty sure they used locked rotor amps to calculate THAT lie... Steve
" look at Volts x amps/745 for more accurate Hp number"
Mark, a MINOR "nit pick" - 1 electrical horsepower is 745.7 watts :laughing:
Also, using that formula only tells you how much horsepower you're INPUTTING; one example - the 5 horse industrial compressor I linked to previously in this thread, uses 21.5 amps @ 240 volts: so it's INPUT power works out to just over 6.9 horsepower. Works out to just over 72% efficiency, IF that Baldor motor's only putting out a REAL 5 horsepower.
And no, I'm NOT gonna hook it up to a rope/pulley/weight and see if it can lift a 550 lb weight more than 5 feet per second :laughing:
Attention Required! | Cloudflare
radios1 - I've seen little 120 volt vertical "roll-around" compressors marked 6 horsepower; pretty sure they used locked rotor amps to calculate THAT lie... Steve
Yep all good stuff guys... thanks for adding additional 'noise' here. :laughing:if someone wants to calculate the kinetic energy of a motor running a 3450 rpm and has a 10 lb. rotor, here's the formula.. Kinetic energy is directly proportional to the mass of the object and to the square of its velocity: K.E. = 1/2 m v2. If the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared. Kinetic energy is usually measured in units of Joules (J); one Joule is equal to 1 kg m2 / s2.