Looks professional Mr. Aquamoose! Guessing you welded on the plate for the rod end of the cylinder to attach?
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To the TBN gallery...
With respect to sizing the cylinder, would a 2.5" cylinder be considered appropriate, or overkill for a 60hp with a heavy 8' EA back blade?
It isnt just the diameter of the cylinder. Its how its attached and the resulting length. Its all a function of leverage.
Take the OP's blade in this example because there is a picture with it where I can estimate some measurements. It looks as though the pivot point on the rod end is ~8" from the center pivot of the blade. Dont know his blade length....but I'll assume its a 6' blade.
Simple math 36"/8" = 4.5
That means for every 1lb of force on the edge of the blade (like snagging the corner on a tree root or curb) means 4.5 pounds of force on the cylinder.
Not even considering shock loads, Lets say his branson is capable of pulling with 2000# of force. That translates to 9000# of force the cylinder must hold. If that "force" is trying to retract the cylinder....that equates to about 5000psi in that base end hose.
Its alot worse if the cylinder is trying to extend. 2000# on the edge of the blade would generate about 9000psi in the rod end hose.
Best case scenario if something is snagged with the blade edge is a blown hose. Worst case would be a bent cylinder rod or ballooned cylinder.
To figure it backwards....lets say the safe limit of the cylinders and hoses are 3000psi. That converts to about 3000 pounds and 5300 pounds of force retracting and extending that the cylinder is good for. Now factor the 4.5:1 leverage ratio.....you get ~660 pounds and ~1200 pounds at the blade end for max force. And thats not hard to generate those forces with a 35hp 4000pound bare weight machine.
So with respect to cylinder diameter.....you can go with a smaller diameter IF you move the pivot point further out (which will require a longer cylinder). Moving the pivot further out reduces the leverage the end of the blade has over the cylinder. And figure the forces based on the retract force of the cylinder (deduct the rod area).
So....a typical 2.5" bore 3000psi welded cylinder has a 1.5" rod. That would be good for about 9400 pounds. If you have a 8' blade and mount your pivot 12" from the king pin (4:1 leverage ratio)....you'd be good for pulling with a force of only about 2350 pounds. And I can assure you a MX can pull alot harder than that.
I think my heavy 8' rear blade that I use behind my MX had either 3.5 or 4" cylinders for the offset and angle. The thing to do is look at existing blades of similar design and see what size cylinders they use for angle and pay attention to the geometry.
The landpride RBT35 series (good match for a MX) has a 3.5" bore, 1.25" rod, 14" stroke cylinder