OP
rswyan
Super Star Member
- Joined
- May 12, 2004
- Messages
- 11,365
- Location
- Northeast Ohio
- Tractor
- Kubota B2910, Cub Cadet Pro Z 154S, Simplicity 18 CFC, Cub Cadet 782
Actually, it is true ...Not really true.
Let's say it takes 15 tons of force to split a particular piece of wood.
Using my rig with the 4" cylinder, it would take 2387 psi to generate that much force ... and about 4.9 hp to generate that 2387 psi @ 3 gpm.
Using jimmy's rig with the 5" cylinder (but with the same pump), it would only take 1500 psi to generate that much force ... and only about 3.0 hp to generate to the 1500 psi @ 3 gpm.
Actually, I'd say it has a lot to do with it ... but I'm assuming a scenario in which one isn't seeing maximum pressure.Diameter of the cylinder, and tonnage it generates, has little to do with the load the motor sees.
No argument there ...You size the motor to the pump.
Of course not ... it's an inanimate object ... it's incapable of feeling or thought ...The motor dont care what size cylinder there is, or how much force the cylinder can generate.
Yup ... that exactly true ... but when it takes less psi to generate the same splitting force, there is less load on the motor.What puts load on the motor is PSI.
That's also true ... but the part highlighted in bold is your qualification.If you have both a 4" cylinder and a 5" cylinder.....and pump set at 2500 psi, the motor is gonna see the exact same load when generating max pressure.....no more.
I didn't qualify my original statement in that manner ... which is why it is potentially true ... but not always true in every case (ie. max pressure)
Yup ... and generating the same force at less pressure = less load on the motor.The difference is .....for that same 2500 PSI, the 5" cylinder can generate more power....but is proportionally slower as well.
Will do ...Looking forward to seeing how the revisions to the lift and wedge work out. Keep us posted