will it take off?

/ will it take off? #401  
NorthwestBlue said:
Larry,

I do understand everything that you wrote and with the Mossroad link. My premis to overcome the "Magic" is to minimize and trivialize its only strength - instant and endless acceleration. The only way that it can transfer energy to the airplane is through friction (the contact between tires and belt). The reason that the links theory fails is TIME. The reason I chose the plane that I did was to emphasize the fact that it would take very little time to create lift and therefore reduce friction and belt induced drag. I chose a design that can accelerate regardless of the state of the wheels. Rotating, stopped (brakes on), or even rotating in reverse has no bearing :D on the outcome.

I agree that given enough time that the MCB would prevent the airplane from taking off. Given enough friction or as you say "traction" then the MCB wins. My idea is to reduce friction or traction and to overpower any negative effects of that friction. My airplane has Teflon wheels. It can out accerate its own wheels. It will accelerate fast enough, and lift will occur fast enough that its own wheels will not be able no maintain the friction to spin up without slipping. Add additional rearward acceleration (MCB) and the wheels just slip faster. Then its just a force drag equation. The plane will fly. If you're still not convinced... I just picked up a few gallons of synthetic oil for my truck and tractor. I could use a little tubing and route a continuous drip on my Teflon wheels. Yee Haw! Come on Mr. ME -three tractor man... Git 'er done. :D :D :D

Oh, and happy Thanksgiving.
Ok - acceleration wont be instant because nothing is, including airplane thrust. Regardless of how quickly it starts it doesnt hit - it shoves. Even an impact is not truly instant. You are right about this idea failing with time in real life. The question is how much time. Im quite positive that even a super plane can be held still for an infinite number of instants -- even longer if there is weight on the wheels during takeoff. Teflon is quite dense. Just machine gearteeth onto the periphery and mate it with a cogged conveyor. Im guessing it would remain still thru several half lifes of ozone. And thats a long time in ozone years.
Larry
 
/ will it take off? #402  
SPYDERLK said:
Ok - acceleration wont be instant because nothing is, including airplane thrust. Regardless of how quickly it starts it doesnt hit - it shoves. Even an impact is not truly instant. You are right about this idea failing with time in real life. The question is how much time. Im quite positive that even a super plane can be held still for an infinite number of instants -- even longer if there is weight on the wheels during takeoff. Teflon is quite dense. Just machine gearteeth onto the periphery and mate it with a cogged conveyor. Im guessing it would remain still thru several half lifes of ozone. And thats a long time in ozone years.
Larry

Oh I see, you are adjusting the parameters so that it can't possibly take off. I was attempting to show that even if you interpret the original question incorrectly an airplane (albeit modified to account for a challenging situation) will take off from this conveyor belt. All planes are built for specific tasks. There is no do all plane. Engineers design planes to operate in the specific environments encountered to accomplish specific tasks. Changing the environments just makes it a little harder.

Acceleration is instantaneous (you can't have motion without it). The magnitude of acceleration and resulting velocity takes time.
 
/ will it take off? #403  
If you make folks think that they are thinking they will like you but if you actually do make them think they won't!

(Don't recall the cite for the paraphrase/plaigerphrase)

This thread has been a real kick even though my humor went unappreciated (and mostly unrecognized) and even drew some comments that were "ungracious."

Reading this has been nearly as much fun as dealing with folks with yet another take on a perpetual motion machine.

Pat
 
/ will it take off? #405  
Hope I'm not repeating someone else, have been away and not read entire thread.

Seems to me that most practical way to duplicate the conveyor belt is to prop a plane up off the ground so wheels not touching the grnd.
Can it fly? Most of the ones I know would not.
Can a plane be build that will, yes I think so.

Take an Radio Control hobby plane,for example.
Hand launch it, most of them you must throw forward at least a little.
Some you can just let go.

Someone mentioned tire pressure and take-off distance, that seems to prove that wheels on the ground matter a good deal.
And that plane on the MCB still aint movin, so no flyin.
 
/ will it take off? #406  
Charlie,

You're missing a point. Being on the conveyor is NOT the "exact same" as holding it in the air and letting go. You need to support it's weight until it achieves enough AIRSPEED to create lift over the wings.

A better way to think of it would be to suspend it on a string and THEN try to take off...of course it would.

The point many of us are trying to make is that the speed of the ground hs no bearing on whether the plane takes off. The tires can be turning a million RPM and it won't matter. What IS important is airspeed and that is achieved irrespective on ANYTHING the ground is doing.

Quit thinking of a car on a dyno sitting there in a stationary position while the rear wheels spin wildly. Think instead of an aircraft engine in a test stand creating thousands of pounds of THRUST trying to rip itself out and go flying.
 
/ will it take off? #407  
joerocker said:
Charlie,

You're missing a point. Being on the conveyor is NOT the "exact same" as holding it in the air and letting go. You need to support it's weight until it achieves enough AIRSPEED to create lift over the wings.

A better way to think of it would be to suspend it on a string and THEN try to take off...of course it would.

The point many of us are trying to make is that the speed of the ground hs no bearing on whether the plane takes off. The tires can be turning a million RPM and it won't matter. What IS important is airspeed and that is achieved irrespective on ANYTHING the ground is doing.

Quit thinking of a car on a dyno sitting there in a stationary position while the rear wheels spin wildly. Think instead of an aircraft engine in a test stand creating thousands of pounds of THRUST trying to rip itself out and go flying.

YIes, that is the whole problem. They are ignoring the major amount of thrust the engine is imparting to the airframe (not to the belt). To remain stationary with respect to the ground:

a.the engine cannot be running.

or

b. Something has to magically do away with some major wind being blasted back by the prop or jet.

Harry K
 
/ will it take off? #408  
turnkey4099 said:
YIes, that is the whole problem. They are ignoring the major amount of thrust the engine is imparting to the airframe (not to the belt). To remain stationary with respect to the ground:

a.the engine cannot be running.

or

b. Something has to magically do away with some major wind being blasted back by the prop or jet.

Harry K

A. The engine can be running. I've stood next to plenty of planes that were running, brakes off, not going anywhere.

B. It is called wind, just like a blow dryer. Your hand doesn't take off.

Think of the conveyor as sucking it to the ground.
 
/ will it take off? #409  
MossRoad said:
A. The engine can be running. I've stood next to plenty of planes that were running, brakes off, not going anywhere.

B. It is called wind, just like a blow dryer. Your hand doesn't take off.

Think of the conveyor as sucking it to the ground.

Okay, now picture the engine running _at take-off power_. What is happening to that energy? All of it is being applied to the airframe, non to the belt. What is keeping the plane from being pulled through the stationary air?

Harry K
 
/ will it take off? #410  
MossRoad,

You're KIDDING right? I SURE hope so!

Stand behind a jet when it's sitting at the end of the runway and applies full throttle and you'll end up being blown quite a distance. Maybe killed. I've seen it flip trucks passing too close behind a jet engine.

You were kidding right?

Give the blow drier enough power and it will flail around wildly "trying" to take off, your hand won't fly unless it's powerful enough to lift your entire body. Which is EXACTLY what an airplane/jet engine IS. It's powerful enough to move the plane fast enough to eventually take of.

You were KIDDING right?

A helicopter is nothing more than a plane that takes off straight up. Would a "magic conveyor belt" stop a helicopter? It's NOT the ground or anything on the ground that affects takeoff.

I KNOW you were kidding...
 
/ will it take off? #411  
Joe, Didn't you appreciate the inertia of the wheels being the "traction" against which the magic conveyor belt worked to hold the plane back? I didn't do the math but spinning the wheels at relativistic speeds is an interesting concept. That puts the conveyor moving at relativistic speeds and the air in contact with it would be accelerated to high speeds, significantly above that required to develop sufficient lift to get the plane out of contact with the conveyor.

Once airborn in this "ground effect" the A/C would begin to accelerate forward. An interesting question is whether or not the A/C would crash when it passed beyond the extent of the conveyor and the high speed airstream generated by it. Inflow air to an air pump is quite difuse and of limited linear extent compared to the outflow. The A/C might even be trapped in ground effect just beyond the end of the conveyor.

Is the action of the conveyor defined for the condition where the A/C lifts off? If the conveyor suddenly stopped when the A/C lifted off the plane would settle back down.

Oh, and it doesn't makek a dimes worth of difference if the plane is a jet, conventional propellor driven (tractor or pusher), turbo prop or propelled by deflating baloons or compressed air tanks.

Patrick
 
/ will it take off? #412  
That plane ain't flying until the wing produces lift. Lift cannot occure unless air pressure exists on the top and bottom of the wing. This only happens with actual motion. Thrust creates the motion. The treadmill prohibits the required motion needed for flight. Myth busted IMHO. I'm sure I've repeated other comments but hey...this is fun.

Cool thread:)
 
/ will it take off? #415  
joerocker said:
A helicopter is nothing more than a plane that takes off straight up. Would a "magic conveyor belt" stop a helicopter? It's NOT the ground or anything on the ground that affects takeoff.

I KNOW you were kidding...

Not the same at all.
 
/ will it take off? #416  
Does the problem actually state that we are considering a fixed wing craft? It's been so long since I read it and there have been so many interpretations, nuances, implications, improvisations and impossible inventions that I'm not sure anymore.

Anyways, just for fun I presented the thing at the Thanksgiving dinner gathering, which included a couple of engineers and some pretty sharp programmers and other thinking type people. There was no agreement since all the familiar trains of thought emerged. The interesting one was my SIL who at first said it would fly, then later decided it wouldn't if the force acting against forward motion through the wheels and induced by the MCB was sufficient to counteract the force acting to produce forward motion by the engine.
 
/ will it take off? #417  
NorthWestBlue, I will address your post point by point:

"Larry,

there is no backward jolt on landing, at least not measurable on an airpeed indicator. There is an almost (Struts, tires, ground all absorb impact) instantaneous arresting of vertical acceleration, but forward velocity remains fairly constant (minus air drag and a very small amount of rolling resistance)." I believe we settled this in a succeeding post; yes, there is a jolt - energy of translational speed is stored rotationaly in the wheels slowing the plane. As you pointed out later, the stored energy is fed back into the airframe as it slows, making it just as hard to stop as if if hadnt slowed as the wheels spun up. - - Good point. Never disagreed before or after you said it. Energy is neither created nor destroyed

"Ok, now somebody help me here. I must be missing something, it's been a long time.

The force due to friction can be determined using various forms of the basic equation: F=muN. Good

where mu (greek letter) is the coefficient of friction. It varies for static or moving (kinetic) and for differing materials. Yes

N is the normal force (in Newtons) which is the mass multiplied by the acceleration due to gravity (9.81m/s^2). F=MA - - yes

Empty weight for U2 in my previous example = 6800kg

Pilot and fuel = 1200kg

Total A/C weight = 8000kg. Good info

mu for rubber is .5 to 1.0. Cool - thats what I thot against road surface

"mu for rolling resistance hard rubber is .01 to .015." Good info,but not germain to the topic of the conveyors action subtracting engine energy from the airframe and storing it in the wheels. This rolling loss would just lessen the wheel acceleration needed to hold the plane still

"mu for steel bearings is .001." Ditto former

"mu for Teflon is .04". Slick stuff. Making skids out of the wheels is, I believe, an abuse of the boundary conditions. The conveyor has always implied wheels. I believe the expected wheels should act AS wheels.

"So, we all seem to agree that the wheels will roll at some point after thrust is applied. Let's use mu for rolling of .015

F=muN
F=(.015)*8000kg*9.81m/s(squared)=1177.2 N" OK, but this is only for wheels turning at speed of motion for whatever they are supporting. The loss causing the retarding Force you calculated is caused by the cyclic flexure of the tires. In resisting the plane thrust the conveyor spins the tires very fast and continues increasing the spin rate in order to store the engines energy output. The tires flex MUCH faster -- they "travel" much further than those that validate the assumptions in your equation. However the equation is right in all cases if used scrupulously. We must look at ENERGY of tire rotation, ei Work per revolution, Force x Distance - or 1177Newtons times the circumference. This, in N*Meters is the amount of energy [work] absorbed in each rev of the wheel. The wheel will heat quickly, dissipating many (and increasing) KiloJoules/sec [kilowatts]. This is subtracted from engine energy rate [power]- gone, not stored in the wheels and just lessens the acceleration requirement for the wheel - conveyor interface. Indeed it would finally use ALL engine power and the conveyor cold stop accelerating.

"The standard U-2R with one Pratt & Whitney J75-P-13B turbojet has a sea level thrust of 76kN (17000 lbf)

76000-1177.2=74822.8 N" Im not sre how to deal with energy here since thrust is just force - not energy or power. Yet I know an engine cannot proguce more energt than it consumes oops-see next post

So we have 74.8kN of thrust to oppose this magical contraption. Throw in that F100 engine in my example with 128.9kN of thrust for even more fun.

Air drag is inconsequential because lift will cancel it out as the airplane accelerates through the air and FLYS.

So can anyone see where I went wrong on my thinking.

Oh, if anyone cares I think RobS answered the original question correctly way back on post #5.
 
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/ will it take off? #418  
Pls see previous post. Hit the wrong button.

76000-1177.2=74822.8 N" Im not sre how to deal with energy here since thrust is just force - not energy or power. Yet I know an engine cannot produce more energy than it consumes nor at a faster rate than it consumes it, and the rate that thetires are absorbing energy is increasing.

So we have 74.8kN of thrust to oppose this magical contraption. Throw in that F100 engine in my example with 128.9kN of thrust for even more fun.
No rockets allowed in this problem. We cant stand that much fun.

Air drag is inconsequential because lift will cancel it out as the airplane accelerates through the air and FLYS.

So can anyone see where I went wrong on my thinking. Well yeah. Significant redefinition of the scenario by converting to skidders and a rocket engine notwithstanding, you introduced real world variables that only make it more difficult for the plane to take off.

Oh, if anyone cares I think RobS answered the original question correctly way back on post #5. Yep. Unless the original was asking us to think a little further on the implication that forward motion was prevented.
Larry
 
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/ will it take off? #420  
joerocker said:
MossRoad,

You're KIDDING right? I SURE hope so!

Stand behind a jet when it's sitting at the end of the runway and applies full throttle and you'll end up being blown quite a distance. Maybe killed. I've seen it flip trucks passing too close behind a jet engine.

You were kidding right?

Give the blow drier enough power and it will flail around wildly "trying" to take off, your hand won't fly unless it's powerful enough to lift your entire body. Which is EXACTLY what an airplane/jet engine IS. It's powerful enough to move the plane fast enough to eventually take of.

You were KIDDING right?

A helicopter is nothing more than a plane that takes off straight up. Would a "magic conveyor belt" stop a helicopter? It's NOT the ground or anything on the ground that affects takeoff.

I KNOW you were kidding...

Same here and I was wondering before I posted my last reply.

Harry K
 

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