How much PSI in each of the two scenarios? 5x12 bed, two 3500# axles, max load 5000#. Also, I picked up a "basket" of Moss Rock yesterday that weighed 3009 lbs (with skid and wire cage.) I saw no difference in the lifting action (like there was no weight at all) and no difference in the sudden drop if I held the remote on the way down. How come the really flat triangle formed by the two points on the cylinder and the hinge of the bed has no visible effect through the range of motion going up and is the exact opposite going down? Would it be a different story if I put 5000 lbs on it?
The "secrets" about dumping a bed like this are many.
1. Where is center of gravity of the bed and load combined?
2. Where is the cylinder affix point to the bed?
3. Where is the cylinder affix point to the trailer frame?
4. Where is the hinge point between bed and trailer frame?
These things will determine the size of the load (Force), the cylinder have to overcome.
5. The bore diameter (piston area) will then determine the required pressure to lift bed.
6. While bed is pivoting during the dump cycle, the effective cylinder force will change. The way your current design is, cylinder is least effective when bed is all the way down., and most effective when cylinder is fully extended (square to the bed). That means the highest pressure is required at the start of the dump cycle.
This drawing illustrates the complexity of forces and distances on a design like this. What ever your actual numbers are, everything can be calculated.
The most interesting during the dump cycle, happens within the yellow shaded area. I leave it open for discussion.